Question

我在Jenkins管道中的groovy配置：

HttpUriRequest postRequestLogin = new HttpPost();

List<NameValuePair> urlParameters = new ArrayList<NameValuePair>();
urlParameters.add(new BasicNameValuePair("j_username", "${user}"))
urlParameters.add(new BasicNameValuePair("j_password", "${pass}"))
postRequestLogin.setEntity(new UrlEncodedFormEntity(urlParameters))

CloseableHttpResponse responseLogin = httpClient.execute(postRequestLogin)

我收到以下错误：

没有方法签名： org.apache.http.impl.client.InternalHttpClient.execute（）适用对于参数类型：（org.apache.http.client.methods.HttpPost）值： [org.apache.http.client.methods.HttpPost@eb47360]可能的解决方案：执行（org.apache.http.client.methods.HttpUriRequest），执行（org.apache.http.client.methods.HttpUriRequest， org.apache.http.client.ResponseHandler） execute（org.apache.http.HttpHost，org.apache.http.HttpRequest），执行（org.apache.http.client.methods.HttpUriRequest， org.apache.http.protocol.HttpContext） execute（org.apache.http.HttpHost，org.apache.http.HttpRequest， org.apache.http.client.ResponseHandler）执行（org.apache.http.client.methods.HttpUriRequest， org.apache.http.client.ResponseHandler， org.apache.http.protocol.HttpContext）

Answer 1

提出请求的其他方式：

    URL url = url_string.toURL()
    // Create authorization header format using Base64 encoding
    String userpass = username + ":" + apiKey;
    String basicAuth = "Basic " + javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes());
    // Open connection
    URLConnection connection = url.openConnection()

    connection.setRequestProperty ("Authorization", basicAuthString())
    connection.setRequestMethod("POST")
    connection.doOutput = false;

    // Open input stream
    InputStream inputStream = connection.getInputStream()
    // Close the stream
    inputStream.close()

    return connection.getResponseCode()

Jenkins管道无法执行HttpClient.execute（HttpPost）

1 个答案: