Question

我正在使用Google距离矩阵api来获取位置之间的距离。所以我使用了这个查询：

String distanceofloc="https://maps.googleapis.com/maps/api/distancematrix/json?origins="+mylat+","+mylng+"&destinations="+placeloc+"&key=MY_BROWSER_KEY";

然后我用一个函数调用了一个函数来获取距离：

String dis=setDistance(distanceofloc);

这是我的 setDistance 功能：

public String setDistance(String url) throws URISyntaxException{
    String dis=null;
    StringBuilder placesBuilder = new StringBuilder();

        //execute search

        HttpClient placesClient = new DefaultHttpClient();
        HttpResponse placesResponse=null;
            //try to fetch the data
        try{
            HttpPost placesGet = new HttpPost(url);


            try{
                placesResponse = placesClient.execute(placesGet);

            }catch(Exception e){
                e.printStackTrace();
                Log.v("PLACES", "exception thrown");
            }

            StatusLine placeSearchStatus = placesResponse.getStatusLine();



            if (placeSearchStatus.getStatusCode() == 200) {
                //we have an OK response


                HttpEntity placesEntity = placesResponse.getEntity();
                InputStream placesContent = placesEntity.getContent();
                //create reader
                InputStreamReader placesInput = new InputStreamReader(placesContent);
                //use buffered reader to process
                BufferedReader placesReader = new BufferedReader(placesInput);
                //read a line at a time, append to string builder
                String lineIn;
                while ((lineIn = placesReader.readLine()) != null) {
                    placesBuilder.append(lineIn);
                }}}
                catch(Exception e){
                    e.printStackTrace();
                    Log.v("PLACES", "missing value");
                }




    try {
        //parse JSON

        //create JSONObject, pass stinrg returned from doInBackground

        JSONObject distanceJSONObject = new JSONObject(placesBuilder.toString());

        JSONArray rowArray = distanceJSONObject.getJSONArray("rows");

        JSONObject rowsObject = rowArray.getJSONObject(0);//only one element in this array


        JSONArray elementsArray = rowsObject.getJSONArray("elements");

        JSONObject elementsObject = elementsArray.getJSONObject(0);//only one element in this array
        if(elementsObject.isNull("distance")){

        }
        else{
       JSONObject distanceObject = elementsObject.getJSONObject("distance");
       if(!distanceObject.isNull("text"))
       { 
        dis=distanceObject.getString("text"



       }

    }



    }catch (JSONException e) {
        e.printStackTrace();

    }


    return dis;

}

此处，异常被抛出

HttpPost placesGet = new HttpPost(url);


            try{
                placesResponse = placesClient.execute(placesGet);

            }catch(Exception e){
                e.printStackTrace();
                Log.v("PLACES", "exception thrown");
            }

任何人都可以告诉我网址是否有问题吗？感谢任何帮助。

Answer 1

您不允许在主UI线程上执行任何网络io。 Android Framework提供了解决此限制的特定方法。您应该使用Worker Threads or AsyncTask来处理与您有关的所有与网络相关的事情。

编辑：

这是我最初的建议。它可能对其他人有用。

从我的头脑中，您是否拥有Manifest.xml访问互联网的权限？

的内容

<manifest ...>
  ...
  <uses-permission android:name="android.permission.INTERNET"></uses-permission>
</manifest>

这在尝试连接到任何服务器时会导致异常。

httpclient.execute（httppost）抛出异常

1 个答案: