Question

我开发了一个将数据发送到服务器的应用程序但是当我尝试运行它时，我在执行http请求时遇到错误....

这是代码......

    public void send()
    {
        // get the message from the message text box
        String msg = msgTextField.getText().toString();  
        System.out.println("I am here!!!");
        // make sure the fields are not empty
        if (msg.length()>0)
        {

            Toast.makeText(this, "started", Toast.LENGTH_LONG).show();
            DefaultHttpClient httpclient=new DefaultHttpClient();
            HttpPost httppost = new HttpPost("http://www.fblocation.asia/update/index.php");
           List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
           nameValuePairs.add(new BasicNameValuePair("lat", Double.toString(clat)));
           nameValuePairs.add(new BasicNameValuePair("long", Double.toString(clong)));
           nameValuePairs.add(new BasicNameValuePair("username", msg));
         try {
           httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
           httpclient.execute(httppost);
           Toast.makeText(this, "sent", Toast.LENGTH_LONG).show();
         } catch (Exception e) {
             Toast t=Toast.makeText(getApplicationContext(),e.getMessage(), Toast.LENGTH_LONG);
             t.show();
         }

        }
        else
        {
            // display message if text fields are empty
            Toast.makeText(getBaseContext(),"All field are required",Toast.LENGTH_SHORT).show();
        }

    }

请给我一些建议。

谢谢！

Answer 1

请尝试此代码

HttpClient httpclient = new DefaultHttpClient();
        String responseStr="";
        String URL=Constants.API_URL+"details/";
        HttpPost httppost = new HttpPost(URL);

        try {
            // Add your data
            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
            nameValuePairs.add(new BasicNameValuePair("id", pick_up_id));
            nameValuePairs.add(new BasicNameValuePair("username", username));
            nameValuePairs.add(new BasicNameValuePair("password", password));
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            // Execute HTTP Post Request
            HttpResponse response = httpclient.execute(httppost);

            int responseCode = response.getStatusLine().getStatusCode();
            switch(responseCode) {
            case 200:
                HttpEntity entity = response.getEntity();
                if(entity != null) {
                    String responseBody = EntityUtils.toString(entity);
                    responseStr=responseBody;
                }
                break;
            }
        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
        } catch (IOException e) {
            // TODO Auto-generated catch block
        }
        System.out.println("this is response "+responseStr);

Answer 2

你必须异步进行http调用。这意味着您的代码和一些练习日的一些重大变化。按照评论中的链接获取AsyncTask的第一印象。

this guide也很稳固!!

httpclient.execute（httppost）出错;

2 个答案: