PHP array_merge在类中返回null

Question

为什么此代码返回null？
我检查它，但没有错误，当我调用数组合并2默认数组像 [＆＃34; x＆＃34; =＆gt;＆＃34; y＆＃34;，＆＃34; foo＆ ＃34; =＆gt;＆＃34; bar＆＃34;] 效果很好！
参见：

<?php
class ClassName
{
    private $dataArray = array();
    public function put($arr){
        $this->dataArray = array_merge($arr,$this->dataArray);
        return $this;
    }    
    public function run(){
        echo json_encode($this->dataArray);
    }
}

$json = new ClassName();

$json->Test->LastLog = '123456789123456';
$json->Password      = 'Mypassword';
$json->Dramatic      = 'Cat';
$json->Things        = array("HI" => 1, 2, 3);

$json->put($json)->run();

Answer 1

你传递了一个不是数组的对象试试这个代码得到的结果：

$json->put((array)$json)->run();

输出是：

> {"\u0000ClassName\u0000dataArray":["Volvo XC90","BMW
> M4","MaclarenP1"],"Test":"123456789123456","Password":"Mypassword","Dramatic":"Cat","Things":{"HI":1,"0":2,"1":3},"0":"Volvo
> XC90","1":"BMW M4","2":"MaclarenP1"}

修改 如果你想传递$json->Test->LastLog这样的意思，你需要交替使用对象声明，如：

$json = new ClassName();

$json->Test = array('LastLog'=>'123456789123456');
$json->Password      = 'Mypassword';
$json->Dramatic      = 'Cat';
$json->Things        = array("HI" => 1, 2, 3);

因为你的put函数是array_merge期望的数组但是你发送了一个json_object而不是数组。 （数组）就像json_decode一样...... 示例：简单对象

$object = new StdClass;
$object->foo = 1;
$object->bar = 2;

var_dump( (array) $object );

输出：

array(2) {
  'foo' => int(1)
  'bar' => int(2)
}