我有数据,我将它们返回到集合中,但没有如我所愿返回,我需要帮助修复它。
array:11 [▼
0 => Collection {#2762 ▼
#items: array:3 [▼
0 => Product {#2758 ▶}
1 => Product {#2759 ▶}
2 => Product {#2760 ▶}
]
}
1 => Collection {#2792 ▼
#items: []
}
2 => Collection {#2948 ▼
#items: []
}
3 => Collection {#3102 ▼
#items: []
}
4 => Collection {#3216 ▼
#items: []
}
5 => Collection {#2886 ▼
#items: array:10 [▶]
}
6 => Collection {#2920 ▼
#items: array:3 [▶]
}
7 => Collection {#3046 ▼
#items: array:12 [▶]
}
8 => Collection {#3074 ▼
#items: []
}
9 => Collection {#3188 ▼
#items: array:7 [▶]
}
10 => Collection {#3288 ▼
#items: []
}
]
$category = Category::where('slug','=',$catslug)->with('childs', 'parent')->first();
$pp1[] = Product::where('category_id',$category->id)->get();
foreach($category->childs as $first){
$pp2[] = Product::where('category_id',$first->id)->get();
if(count($first->childs)> 0){
foreach($first->childs as $second){
$pp3[] = Product::where('category_id',$second->id)->get();
}
}
}
$products = array_merge($pp1,$pp2,$pp3);
dd($products);
它应该仅从1个数组中的所有数组中返回所有产品,而不是按Collection {#2792 ▼
分类。我只需要获取包含项目的集合,而不是空项目。
有什么主意吗?
我也尝试过:
$pp1 = [];
$pp2 = [];
$pp3 = [];
$pp1 = Product::where('category_id',$category->id)->get();
foreach($category->childs as $first){
$pp2 = Product::where('category_id',$first->id)->get();
if(count($first->childs)> 0){
foreach($first->childs as $second){
$pp3 = Product::where('category_id',$second->id)->get();
}
}
}
它返回:
array_merge(): Argument #1 is not an array
答案 0 :(得分:0)
您可以获取该类别的所有产品,包括其子代和孙子代,
$category = Category::where('slug','=',$catslug)
->with([
'products',
'childs.products',
'childs.childs.products',
'parent'
])
->first()
->toArray();
$products = array_merge([
data_get($category, 'products'),
array_collapse(data_get($category, 'childs.*.products')),
array_collapse(data_get($category, 'childs.*.childs.*.products'))
]);