Question

我有一个$ mentor_fails数组，该数组跟踪未能插入数据库表的指导者。虽然，我遇到了插入失败的异常，但是我的$ mentor_fails似乎没有将包含失败的指导者信息的对象保存到$ mentor_fails中。请让我知道我做错了。

function assign_mentors_and_projects($mentors,$projects){
    global $mydb; 

    $mentor_fails = array();

    foreach($mentors as $mentor){
        foreach($projects as $project){
            try {
                $update_mentors_and_projects_rlshp = $mydb->insert(
                    'abcdefg',
                    array('project_id'=>$project, 'mentor_id'=>$mentor),
                    array('%s','%s'));

                    if($update_mentors_and_projects_rlshp == false) {
                        array_merge($mentor_fails, array('mentor_email'=>$mentor, 'project_id'=>$project));
                        throw new Exception("exist already:(mentor-".$mentor." project_id-".$project.")\r\n");
                    }
            } catch (Exception $e) {
                echo $e->getMessage();
            }
        }
    }

    return $mentor_fails;

}`

Answer 1

我认为问题在于array_merge不能通过引用合并。

来自PHP doc：

array_merge（array $ array1 [，array $ ...]）：array

此代码段可以解决您的问题。

$mentor_fails= array_merge($mentor_fails, array('mentor_email'=>$mentor, 'project_id'=>$project_id));

我看到您可以添加到$ mentor_fails中，所以您可以像这样：

$mentor_fails[]= array('mentor_email'=>$mentor,'project_id'=>$project_id);

Answer 2

收件人：

array_merge($mentor_fails, array('mentor_email'=>$mentor, 'project_id'=>$project));
throw new Exception("exist already:(mentor-".$mentor." project_id-".$project.")\r\n");

来自：

throw new Exception("exist already:(mentor-".$mentor." project_id-".$project.")\r\n");
array_merge($mentor_fails, array('mentor_email'=>$mentor, 'project_id'=>$project));

PHP的array_merge没有合并，并显示为空

2 个答案: