Question

我已经制作了Android应用程序，当使用Accelerometer摇一次时播放下一首歌。

现在我想要我的应用程序，如果在右侧摇动手机它应该播放下一首歌曲或者如果左前方摇动播放，我可以用在时刻发现的轴的逻辑来做动作如果可能的话 如何将轴置于运动检测方法中以了解移动设备被摇动的方向。如果有人有这方面的逻辑请帮助我被困在这里。

Answer 1

我做了一些挖掘，并能够自己解决它。但是通过 Basil 发布答案我found this answer，这比我的实现更好。所以，我发现它更有帮助。

他做了什么

在 onSensorChanged 中，只要设备收到新值，它就会在延迟一段时间后将值存储到变量中。之后将新值与之前的值进行精美比较。这导致计算设备震动的方向。如果答案仍然不清楚，请告诉我。

public class ShakeActivity extends Activity implements SensorListener {
// For shake motion detection.
private SensorManager sensorMgr;
private long lastUpdate = -1;
private float x, y, z;
private float last_x, last_y, last_z;
private static final int SHAKE_THRESHOLD = 800;

protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);

setContentView(R.layout.main);
// start motion detection
sensorMgr = (SensorManager) getSystemService(SENSOR_SERVICE);
boolean accelSupported = sensorMgr.registerListener(this,
    SensorManager.SENSOR_ACCELEROMETER,
    SensorManager.SENSOR_DELAY_GAME);

    if (!accelSupported) {
        // on accelerometer on this device
        sensorMgr.unregisterListener(this,
                SensorManager.SENSOR_ACCELEROMETER);
    }
}

protected void onPause() {
    if (sensorMgr != null) {
        sensorMgr.unregisterListener(this,
                SensorManager.SENSOR_ACCELEROMETER);
        sensorMgr = null;
    }
    super.onPause();
}

public void onAccuracyChanged(int arg0, int arg1) {
// TODO Auto-generated method stub
}

public void onSensorChanged(int sensor, float[] values) {
    if (sensor == SensorManager.SENSOR_ACCELEROMETER) {
        long curTime = System.currentTimeMillis();
        // only allow one update every 100ms.
        if ((curTime - lastUpdate) > 100) {
        long diffTime = (curTime - lastUpdate);
        lastUpdate = curTime;

        x = values[SensorManager.DATA_X];
        y = values[SensorManager.DATA_Y];
        z = values[SensorManager.DATA_Z];

        if(Round(x,4)>10.0000){
            Log.d("sensor", "X Right axis: " + x);
            Toast.makeText(this, "Right shake detected", Toast.LENGTH_SHORT).show();
        }
        else if(Round(x,4)<-10.0000){
            Log.d("sensor", "X Left axis: " + x);
            Toast.makeText(this, "Left shake detected", Toast.LENGTH_SHORT).show();
        }

        float speed = Math.abs(x+y+z - last_x - last_y - last_z) / diffTime * 10000;

        // Log.d("sensor", "diff: " + diffTime + " - speed: " + speed);
        if (speed > SHAKE_THRESHOLD) {
            //Log.d("sensor", "shake detected w/ speed: " + speed);
            //Toast.makeText(this, "shake detected w/ speed: " + speed, Toast.LENGTH_SHORT).show();
        }
        last_x = x;
        last_y = y;
        last_z = z;
        }
    }
}

public static float Round(float Rval, int Rpl) {
float p = (float)Math.pow(10,Rpl);
Rval = Rval * p;
float tmp = Math.round(Rval);
return (float)tmp/p;
}
}

使用摇动动作从加速度计获取方向

1 个答案: