我想获得一个记录集，我可以用关系表来比较结果：
character_abilities
id ability_id character_id
1 1 43
2 2 43
3 5 43
4 7 43
5 8 43
6 9 43
7 1 75
8 2 75
9 3 75
10 5 75
我想得到这样的结果：
ability_id_1 character_id_1 ability_id_2 character_id_2
1 43 1 75
2 43 2 75
NULL NULL 3 75
5 43 5 75
7 43 NULL NULL
8 43 NULL NULL
9 43 NULL NULL
对于这个结果，我想做这样的事情，但没有成功：
SELECT character_1.ability_id AS ability_id_1, character_1.character_id AS character_id_1, character_2.ability_id AS ability_id_2, character_2.character_id AS character_id_2
FROM character_abilities AS character_1
RIGHT JOIN character_abilities AS character_2
ON character_2.character_id = 2 AND character_1.ability_id = character_2.ability_id
WHERE character_1.character_id = 1 AND character_1.ability_id = character_2.ability_id
不幸的是，这只返回每个角色的共同能力。
我的问题是：
我可以编写查询来获取每个字符道具，如结果示例吗？
我应该为每个字符进行查询然后将它们合并吗？