Question

我通过命令行从数据帧的时间戳中提取了几个小时：

import pandas as pd  
from datetime import *  
from datetime import datetime  
import datetime as dt  
import time  

df['timestamp'] = pd.to_datetime(df['timestamp'])  
df['time'] = df['timestamp'].dt.time  
df['time']

Output: id      time
        3539    23:49:58  
        3540    23:52:39  
        3541    23:55:19  
        3542    23:58:00  
        Name: time, dtype: object

我需要将时间列转换为秒，即 23:49:58 = 23 * 3600 + 49 * 60 + 58 = 85798秒

id   time
3539 85798

非常感谢

Answer 1

将日期时间转换为hour s，minute和second s：

df['time'] = df['timestamp'].dt.hour * 3600 + 
             df['timestamp'].dt.minute * 60 + 
             df['timestamp'].dt.second

或to_timedelta并获取total_seconds：

df['time'] = pd.to_timedelta(df['timestamp'].dt.strftime('%H:%M:%S'))
               .dt.total_seconds().astype(int)

<强>示例：

df = pd.DataFrame({'timestamp':['2015-04-01 23:49:58','2016-04-01 23:49:58']})
df['timestamp'] = pd.to_datetime(df['timestamp'])  
print (df)
            timestamp
0 2015-04-01 23:49:58
1 2016-04-01 23:49:58

df['time1'] = df['timestamp'].dt.hour * 3600 + \
              df['timestamp'].dt.minute * 60 + \
              df['timestamp'].dt.second

df['time2'] = (pd.to_timedelta(df['timestamp'].dt.strftime('%H:%M:%S'))
                 .dt.total_seconds().astype(int))
print (df)
            timestamp  time1  time2
0 2015-04-01 23:49:58  85798  85798
1 2016-04-01 23:49:58  85798  85798

将小时数转换为秒钟大熊猫

1 个答案: