如何将秒数转换为小时，分钟和秒？
show_time() {
?????
}
show_time 36 # 00:00:36
show_time 1036 # 00:17:26
show_time 91925 # 25:32:05
答案 0 :(得分：70)
#!/bin/sh
convertsecs() {
((h=${1}/3600))
((m=(${1}%3600)/60))
((s=${1}%60))
printf "%02d:%02d:%02d\n" $h $m $s
}
TIME1="36"
TIME2="1036"
TIME3="91925"
echo $(convertsecs $TIME1)
echo $(convertsecs $TIME2)
echo $(convertsecs $TIME3)
浮动秒数：
convertsecs() {
h=$(bc <<< "${1}/3600")
m=$(bc <<< "(${1}%3600)/60")
s=$(bc <<< "${1}%60")
printf "%02d:%02d:%05.2f\n" $h $m $s
}
答案 1 :(得分：38)
我所知道的最简单的方式：
secs=100000
printf '%dh:%dm:%ds\n' $(($secs/3600)) $(($secs%3600/60)) $(($secs%60))
注意 - 如果你想要几天，那么只需添加其他单位并除以86400。
答案 2 :(得分：38)
使用日期，转换为UTC：
$ date -d@36 -u +%H:%M:%S
00:00:36
$ date -d@1036 -u +%H:%M:%S
00:17:16
$ date -d@12345 -u +%H:%M:%S
03:25:45
限制是小时数将在23时循环，但这对于大多数需要单行的用例无关紧要。
在macOS上，运行brew install coreutils并将date替换为gdate
答案 3 :(得分：28)
我自己使用以下功能：
function show_time () {
num=$1
min=0
hour=0
day=0
if((num>59));then
((sec=num%60))
((num=num/60))
if((num>59));then
((min=num%60))
((num=num/60))
if((num>23));then
((hour=num%24))
((day=num/24))
else
((hour=num))
fi
else
((min=num))
fi
else
((sec=num))
fi
echo "$day"d "$hour"h "$min"m "$sec"s
}
注意它也算几天。此外，它显示了您上一个号码的不同结果。
答案 4 :(得分：18)
$ secs=236521
$ printf '%dh:%dm:%ds\n' $(($secs/3600)) $(($secs%3600/60)) $(($secs%60))
65h:42m:1s
$ secs=236521
$ printf '%02dh:%02dm:%02ds\n' $(($secs/3600)) $(($secs%3600/60)) $(($secs%60))
65h:42m:01s
$ secs=236521
$ printf '%dd:%dh:%dm:%ds\n' $(($secs/86400)) $(($secs%86400/3600)) $(($secs%3600/60)) \
$(($secs%60))
2d:17h:42m:1s
$ secs=21218.6474912
$ printf '%02dh:%02dm:%02fs\n' $(echo -e "$secs/3600\n$secs%3600/60\n$secs%60"| bc | xargs echo)
05h:53m:38.647491s
答案 5 :(得分：10)
对于我们懒惰的人：https://github.com/k0smik0/FaCRI/blob/master/fbcmd/bin/displaytime提供现成的脚本：
#!/bin/bash
function displaytime {
local T=$1
local D=$((T/60/60/24))
local H=$((T/60/60%24))
local M=$((T/60%60))
local S=$((T%60))
[[ $D > 0 ]] && printf '%d days ' $D
[[ $H > 0 ]] && printf '%d hours ' $H
[[ $M > 0 ]] && printf '%d minutes ' $M
[[ $D > 0 || $H > 0 || $M > 0 ]] && printf 'and '
printf '%d seconds\n' $S
}
displaytime $1
基本上只是另一个解决方案的另一个旋转，但有额外的好处，抑制空时间单位（f.e。10 seconds而不是0 hours 0 minutes 10 seconds）。无法完全跟踪函数的原始来源，发生在多个git repos ..
答案 6 :(得分：5)
以上所有内容均适用于bash，无视“＃！/ bin / sh” 没有任何基础将是：
convertsecs() {
h=`expr $1 / 3600`
m=`expr $1 % 3600 / 60`
s=`expr $1 % 60`
printf "%02d:%02d:%02d\n" $h $m $s
}
答案 7 :(得分：5)
t=12345;printf %02d:%02d:%02d\\n $((t/3600)) $((t%3600/60)) $((t%60)) # POSIX
echo 12345|awk '{printf "%02d:%02d:%02d",$0/3600,$0%3600/60,$0%60}' # POSIX awk
date -d @12345 +%T # GNU date
date -r 12345 +%T # OS X's date
如果其他人正在寻找如何做反向：
IFS=: read h m s<<<03:25:45;echo $((h*3600+m*60+s)) # POSIX
echo 03:25:45|awk -F: '{print 3600*$1+60*$2+$3}' # POSIX awk
答案 8 :(得分：3)
我无法让Vaulter / chepner的代码正常工作。我认为正确的代码是：
convertsecs() {
h=$(($1/3600))
m=$((($1/60)%60))
s=$(($1%60))
printf "02d:%02d:%02d\n $h $m $s
}
答案 9 :(得分：2)
在一行中：
show_time () {
if [ $1 -lt 86400 ]; then
date -d@${1} -u '+%Hh:%Mmn:%Ss';
else
echo "$(($1/86400)) days $(date -d@$(($1%86400)) -u '+%Hh:%Mmn:%Ss')" ;
fi
}
如果存在则添加天数。
答案 10 :(得分：2)
MacOS 特定的答案，它使用 OOTB /bin/date 并且不需要需要 date 的 GNU 版本：
# convert 195 seconds to MM:SS format, i.e. 03:15
/bin/date -j -f "%s" 195 "+%M:%S"
## OUTPUT: 03:15
答案 11 :(得分：1)
这是一个旧的后卵巢 - 但是，对于那些可能正在寻找实际时间但以军事形式（00：05：15：22 - 而不是0：5：15：22）的人
!#/bin/bash
num=$1
min=0
hour=0
day=0
if((num>59));then
((sec=num%60))
((num=num/60))
if((num>59));then
((min=num%60))
((num=num/60))
if((num>23));then
((hour=num%24))
((day=num/24))
else
((hour=num))
fi
else
((min=num))
fi
else
((sec=num))
fi
day=`seq -w 00 $day | tail -n 1`
hour=`seq -w 00 $hour | tail -n 1`
min=`seq -w 00 $min | tail -n 1`
sec=`seq -w 00 $sec | tail -n 1`
printf "$day:$hour:$min:$sec"
exit 0
答案 12 :(得分：0)
从@ eMPee584的代码轻微编辑，将其全部放在一个GO中（将该函数放入一些.bashrc文件中并将其作为源码使用，将其用作myuptime。对于非Mac OS，将T公式替换为一个给出秒的公式自上次启动以来。
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答案 13 :(得分：0)
使用dc：
$ echo '12345.678' | dc -e '?1~r60~r60~r[[0]P]szn[:]ndZ2>zn[:]ndZ2>zn[[.]n]sad0=ap'
3:25:45.678
表达式?1~r60~r60~rn[:]nn[:]nn[[.]n]sad0=ap执行以下操作：
? read a line from stdin
1 push one
~ pop two values, divide, push the quotient followed by the remainder
r reverse the top two values on the stack
60 push sixty
~ pop two values, divide, push the quotient followed by the remainder
r reverse the top two values on the stack
60 push sixty
~ pop two values, divide, push the quotient followed by the remainder
r reverse the top two values on the stack
[ interpret everything until the closing ] as a string
[0] push the literal string '0' to the stack
n pop the top value from the stack and print it with no newline
] end of string, push the whole thing to the stack
sz pop the top value (the string above) and store it in register z
n pop the top value from the stack and print it with no newline
[:] push the literal string ':' to the stack
n pop the top value from the stack and print it with no newline
d duplicate the top value on the stack
Z pop the top value from the stack and push the number of digits it has
2 push two
>z pop the top two values and executes register z if the original top-of-stack is greater
n pop the top value from the stack and print it with no newline
[:] push the literal string ':' to the stack
n pop the top value from the stack and print it with no newline
d duplicate the top value on the stack
Z pop the top value from the stack and push the number of digits it has
2 push two
>z pop the top two values and executes register z if the original top-of-stack is greater
n pop the top value from the stack and print it with no newline
[ interpret everything until the closing ] as a string
[.] push the literal string '.' to the stack
n pop the top value from the stack and print it with no newline
] end of string, push the whole thing to the stack
sa pop the top value (the string above) and store it in register a
d duplicate the top value on the stack
0 push zero
=a pop two values and execute register a if they are equal
p pop the top value and print it with a newline
每个操作后具有堆栈状态的示例执行：
: <empty stack>
? : 12345.678
1 : 1, 12345.678
~ : .678, 12345
r : 12345, .678 # stack is now seconds, fractional seconds
60 : 60, 12345, .678
~ : 45, 205, .678
r : 205, 45, .678 # stack is now minutes, seconds, fractional seconds
60 : 60, 205, 45, .678
~ : 25, 3, 45, .678
r : 3, 25, 45, .678 # stack is now hours, minutes, seconds, fractional seconds
[[0]n] : [0]n, 3, 25, 45, .678
sz : 3, 25, 45, .678 # '[0]n' stored in register z
n : 25, 45, .678 # accumulated stdout: '3'
[:] : :, 25, 45, .678
n : 25, 45, .678 # accumulated stdout: '3:'
d : 25, 25, 45, .678
Z : 2, 25, 45, .678
2 : 2, 2, 25, 45, .678
>z : 25, 45, .678 # not greater, so register z is not executed
n : 45, .678 # accumulated stdout: '3:25'
[:] : :, 45, .678
n : 45, .678 # accumulated stdout: '3:25:'
d : 45, 45, .678
Z : 2, 45, 45, .678
2 : 2, 2, 45, .678
>z : 45, .678 # not greater, so register z is not executed
n : .678 # accumulated stdout: '3:25:45'
[[.]n] : [.]n, .678
sa : .678 # '[.]n' stored to register a
d : .678, .678
0 : 0, .678, .678
=a : .678 # not equal, so register a not executed
p : <empty stack> # accumulated stdout: '3:25:45.678\n'
在0小数秒的情况下：
: 3, 25, 45, 0 # starting just before we begin to print
n : 25, 45, .678 # accumulated stdout: '3'
[:] : :, 25, 45, .678
n : 25, 45, .678 # accumulated stdout: '3:'
d : 25, 25, 45, .678
Z : 2, 25, 45, .678
2 : 2, 2, 25, 45, .678
>z : 25, 45, .678 # not greater, so register z is not executed
n : 45, .678 # accumulated stdout: '3:25'
[:] : :, 45, .678
n : 45, .678 # accumulated stdout: '3:25:'
d : 45, 45, .678
Z : 2, 45, 45, .678
2 : 2, 2, 45, .678
>z : 45, .678 # not greater, so register z is not executed
n : .678 # accumulated stdout: '3:25:45'
[[.]n] : [.]n, 0
sa : 0 # '[.]n' stored to register a
d : 0, 0
0 : 0, 0, 0
=a : 0 # equal, so register a executed
[.] : ., 0
n : 0 # accumulated stdout: '3:35:45.'
p : <empty stack> # accumulated stdout: '3:25:45.0\n'
如果分钟值小于10：
: 3, 9, 45, 0 # starting just before we begin to print
n : 9, 45, .678 # accumulated stdout: '3'
[:] : :, 9, 45, .678
n : 9, 45, .678 # accumulated stdout: '3:'
d : 9, 9, 45, .678
Z : 1, 9, 45, .678
2 : 2, 1, 9, 45, .678
>z : 9, 45, .678 # greater, so register z is executed
[0] : 0, 9, 45, .678
n : 9, 45, .678 # accumulated stdout: '3:0'
n : 9, .678 # accumulated stdout: '3:09'
# ...and continues as above
编辑：这有一个错误，可以打印7：7：34.123之类的字符串。我已对其进行了修改，以在必要时打印前导零。
答案 14 :(得分：0)
又一个版本。仅处理完整整数，不填充 0:
format_seconds() {
local sec tot r
sec="$1"
r="$((sec%60))s"
tot=$((sec%60))
if [[ "$sec" -gt "$tot" ]]; then
r="$((sec%3600/60))m:$r"
let tot+=$((sec%3600))
fi
if [[ "$sec" -gt "$tot" ]]; then
r="$((sec%86400/3600))h:$r"
let tot+=$((sec%86400))
fi
if [[ "$sec" -gt "$tot" ]]; then
r="$((sec/86400))d:$r"
fi
echo "$r"
}
$ format_seconds 59
59s
$ format_seconds 60
1m:0s
$ format_seconds 61
1m:1s
$ format_seconds 3600
1h:0m:0s
$ format_seconds 236521
2d:17h:42m:1s