Question

我需要知道5次投掷硬币的“头”和“尾”的得分。例如，结果应该是： - 头部是3次 - 尾巴是2次

import random
print("Heads or tails. Let's toss a coin five times.\n")
toss = 1

while toss <= 5:
    coin = ["HEADS", "TAILS"]
    y = random.choice(coin)
    print("Toss number:", toss, "is showing:", y)
    toss = toss + 1

Answer 1

我已对代码进行了更改，以计算每个硬币面（头部或尾部）的频率，

import random
print("Heads or tails. Let's toss a coin five times.\n")
toss = 1
counts = {"HEADS": 0, "TAILS": 0}

while toss <= 5:
    coin = ["HEADS", "TAILS"]
    y = random.choice(coin)
    counts[y] += 1
    print("Toss number:", toss, "is showing:", y)
    toss = toss + 1

print("Heads was " + str(counts["HEADS"]) + " times - Tails was " + str(counts["TAILS"]) + " times")

Answer 2

您应该有两个变量，head和tail：

import random
print("Heads or tails. Let's toss a coin five times.\n")
head = tail = 0

for i in range(5):
    coin = ["HEADS", "TAILS"]
    y = random.choice(coin)
    print("Toss number:", i, "is showing:", y)
    if y == "HEADS":
        head += 1
    elif y == "TAILS":
        tail += 1

或者，更好的解决方案是使用带有表示头部和尾部的键的字典，其值代表计数。

Answer 3

一个简单的解决方案是让toss成为抛硬币结果列表。从空列表开始，您可以循环直到列表包含5个结果，并在每次折腾时将新成员推入列表。这样，您最终会得到一个包含所有关于投掷所需信息的数据结构。

Answer 4

创建两个变量，将它们初始化为0，检查if块中掷硬币的结果并相应添加。

heads, tails = 0, 0
if y == "HEADS":
    heads += 1
else:
    tails += 1

return (heads, tails)

Python - while循环计数

4 个答案: