Question

SELECT DISTINCT 
   F_Emp_code,CONVERT(varchar, t.F_Log_dtPunched, 103) AS F_Tbl_dtpunched,

  Loc.F_Loc_code,COUNT(TF.F_Ter_LocCode)'Worked'
  FROM 
   (select *, row_number() over (partition by F_Emp_code order by F_Emp_code) as rn from T_Mst_Employee )  A 
   LEFT JOIN T_Mst_Company co ON co.F_Com_code = A.F_Emp_Company_ID     
   RIGHT JOIN T_Tra_Loginfo t ON t.F_Log_Emp_Code = F_Emp_code  
   JOIN   dbo.T_Mst_terminalinfo TF ON TF.F_Ter_nTerminalID=t.F_Log_TerminalID
   LEFT JOIN T_Mst_Location Loc ON Loc.F_Loc_code = TF.F_Ter_LocCode
   WHERE A.F_Emp_Status = 'Active'   
   AND F_Emp_code='100229'
   and  t.F_Log_dtPunched between '2017-01-01' and '2017-01-08' 
   group by co.F_Com_Logo, A.f_emp_firstname,A.F_Emp_MiddleName,
   A.F_Emp_LastName,F_Emp_code,
   F_Log_dtPunched,co.F_Com_Desc,Loc.F_Loc_code,Loc.F_Loc_Desc,TF.F_Ter_nTerminalID



My result is like this :
empid     date      loccode  worktime
100229  01/01/2017  05138   1
100229  02/01/2017  05138   1
100229  03/01/2017  05138   1
100229  05/01/2017  09409   1
100229  06/01/2017  05138   1
100229  07/01/2017  01305   1
100229  07/01/2017  05138   1

如果任何员工使用不同的位置工作相同的日期，那么我想在工作时间显示结果= 1 /不同位置的计数

例如，如果员工在同一天工作了3个位置，那么我需要计算工作时间列1/3的工作时间

Answer 1

您正在寻找COUNT(DISTINCT column) OVER (...)：

worktime * 1.0 / count(distinct loccode) over (partition by emp_id, date)

为了避免整数除法，必须乘以1.0。

计算结果除以其他字段的否

1 个答案: