Question

我正在尝试在一个点周围创建一个矢量点的'星'，它们之间的角度恒定，并且源和点之间的原始线（见图）我通过创建新的向量来完成与原版相比有一点偏差：

private void FixedUpdate()
{
    ray = Camera.main.ScreenPointToRay(Input.mousePosition);
    if (Physics.Raycast(ray, out hit, 3000))
    {

    Vector3 mousePos = hit.point;
    Debug.DrawLine(transform.position, hit.point, Color.yellow);

    Vector3[] explorePoints = new Vector3[6] {
                new Vector3 (hit.point.x - 1 , hit.point.y, hit.point.z + 1), // diag left
                new Vector3 (hit.point.x + 1 , hit.point.y, hit.point.z + 1), // diag right
                new Vector3 (hit.point.x - 1 , hit.point.y, hit.point.z), // left
                new Vector3 (hit.point.x + 1 , hit.point.y, hit.point.z), // right
                new Vector3 (hit.point.x - 1 , hit.point.y, hit.point.z - 1), // diag left back
                new Vector3 (hit.point.x + 1 , hit.point.y, hit.point.z - 1), // diag right back
    };

    for (int x = 0; x < explorePoints.Length; x++)
    {
        Debug.DrawLine(mousePos, explorePoints[x], Color.red);
    }

}
}

当鼠标之间的角度接近0或180时，这可以正常工作，但当然不是在其他角度：

我知道我可能需要Quaternion类将球体和鼠标点之间的角度应用于方向向量，但不能完全弄明白，例如。

Quaternion q = Quaternion.FromToRotation(transform.position, mousePos);
for (int x = 0; x < explorePoints.Length; x++)
{
      Debug.DrawLine(mousePos, q * explorePoints[x], Color.red);
}

如何始终将 n 角的红线保持在黄线上？

Answer 1

＆＃13;

private void FixedUpdate()
  {
    RaycastHit hit;
    Ray ray = Camera.main.ScreenPointToRay(Input.mousePosition);
    if (Physics.Raycast(ray, out hit, 3000))
    {
      Vector3 mousePos = hit.point;
      Debug.DrawLine(transform.position, hit.point, Color.yellow);
      Vector3 rayDir = transform.position - mousePos;
      Vector3[] explorePoints = new Vector3[6] {
        Quaternion.Euler(0, 0, 45) * rayDir.normalized,
        Quaternion.Euler(0, 0, 90) * rayDir.normalized,
        Quaternion.Euler(0, 0, 135) * rayDir.normalized,
        Quaternion.Euler(0, 0, -45) * rayDir.normalized,
        Quaternion.Euler(0, 0, -90) * rayDir.normalized,
        Quaternion.Euler(0, 0, -135) * rayDir.normalized,
      };

      float starLength = 100;
      for (int x = 0; x < explorePoints.Length; x++)
      {
        // we want to use the vector as DIRECTION, not point, hence mousePos + explorePoints[x] (starLength is just the length of the red line)
        Debug.DrawLine(mousePos, mousePos + (explorePoints[x] * starLength), Color.red);
      }
    }
  }

＆＃13;

相对于方向的统一角度和位置

1 个答案: