我试图从图像中删除blob(Python3)。问题是我在笛卡尔坐标中得到斑点的位置。我的目的是获取blob在矩阵索引中的位置,这样我就可以访问它们并将它们删除(使它们等于零)。
这是我的代码:
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.1/angular.min.js"></script>
<link href="https://netdna.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet">
</head>
<body ng-app="myApp" ng-controller="myCtrl as vm">
<div class="container">
<h3>AUTHORS' LIST</h3>
<div class="btn-group">
<button ng-click="addAuthor()" type="button" class="btn btn-default">Add</button>
<button ng-click="SavelocalStorage()" type="button" class="btn btn-default">Save</button>
</div>
<form ng-controller="booksCtrl" name="vm.myForm">
<table class="table table-bordered">
<tr>
<th>Surname</th>
<th>Name</th>
<th>Books</th>
</tr>
<tr ng-repeat="author in authors">
<td><input ng-model="author.surname" required type="text" class="form-control"></td>
<td><input ng-model="author.name" required type="text" class="form-control"></td>
<td>
<button ng-click="showBookList(author)" type="button" class="btn btn-default">List</button>
</td>
</tr>
</table>
<div ng-show="showBooks" class="col-sm-8" style="background-color:lightblue; position: absolute; left:5px; top:5px;z-index:2;">
<div class="btn-group">
<button ng-click="addBook()" type="button" class="btn btn-default">Add</button>
</div>
<table class="table table-bordered">
<tr>
<th>Title</th>
</tr>
<tr ng-repeat="book in currentAuthor.books">
<td><input ng-model="book.title" type="text" class="form-control"></td>
</tr>
</table>
<button class="btn btn-sm btn-warning" ng-click="showBooks = false">Close</button>
</div>
</form>
</div>
</body>
</html>
关键点是笛卡尔坐标中的内容。我想要的是将其转换为矩阵索引,以便我可以访问图像median2上的相同索引,然后删除blob。
答案 0 :(得分:1)
您的代码:
for j in range(1, len(keypoints)):
x = keypoints[j].pt[0] #i is the index of the blob you want to get the position
y = keypoints[j].pt[1]
median2[x, y] = 0
众所周知,关键点是浮点数,而索引应该是int;我们用[rows,cols]索引图像,即[y,x]。
改性:
for kpt in keypoints:
x = int(pt[0]) # change float to int
y = int(pt[1])
median2[y, x] = 0 # index in [row,col] order, that is (y,x)
您无法通过将blob关键点设置为零来删除小区域。