你会如何水平翻转一个直角三角形，使斜边位于左侧，使用for循环？

Question

我应该将水平上方图像中的三角形翻转，使斜边位于左侧，而不是右侧。我已经尝试了很长时间，似乎无法弄明白。

Answer 1

我想你只想要你得到的输出镜像。请尝试以下代码;

  func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let answerCell = tableView.dequeueReusableCell(withIdentifier: "AnswerCell") as! AnswerCell
   // action added to button
    answerCell.likeButtonClicked.addTarget(self, action: #selector(likeButtonClicked), for: .touchUpInside)
    // updated set tag to button
    answerCell.likeButtonClicked.tag = indexPath.row
    let answer = answers[indexPath.row]
    answerCell.answerText.text = answer.answerText
    answerCell.username.text = "~ \(answer.username)"
    answerCell.numberOfLikes.text = "\(answer.numberOflikes) liked this answer."

    answerCell.answerText.numberOfLines = 0

    return answerCell
}

输出：

 @IBAction func likeButtonClicked(_ sender: UIButton) {
 //updated now tag is row position of button in cell and is equal to       (indexPath.row) of that particular button.tag is equal to 
let tag = sender.tag
 // here indexPath.row can be replace by tag so
  //let answer = answers[indexPath.row] == let answer = answers[tag]
  // updated till here
ref = Database.database().reference()

ref.child("answerLikes").child((answer.id).observeSingleEvent(of: .value, with: {
    (snapshot) in
    if let _ = snapshot.value as? NSNull {
        sender.setImage(UIImage(named: "filledHeart.png"), for: .normal)
    } else {
        answerLikes = [Auth.auth().currentUser?.uid : true]
        ref.child("answerLikes").child(answer.id).updateChildValues(answerLikes)
        sender.setImage(UIImage(named: "emptyHeart.png"), for: .normal)
    }
})
   }

Answer 2

一种简单的方法，保留您已有的代码，将使用格式规范来填充和右对齐输出：

total = 0
x = range(1, 8)

for i in x:
    total = 'T' * i
    print("{:>8}".format(total), end='\n\n')

值得花一点时间来学习print()和str.format()可以执行的各种转换：

> python3 test.py
       T

      TT

     TTT

    TTTT

   TTTTT

  TTTTTT

 TTTTTTT

>