Question

我在分配任务时遇到问题，希望有人能提供帮助。目标是使用多维数组让用户放入直角三角形的side1和side2来确定斜边。现在我被困在两点：

如何使用变量设置数组
如何将这些变量保存到数组中并处理方程式

我的代码当前如下所示：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>

double hypotenuse(double x, double y, double z);

int main(void)
{

    double side1, side2, side3, counter;
    side3 = 1;
    int table[4][3] =
    {
/* Column 0  1  2 */
        { 1, 2, 3 }, // Initializers for for indexed by 0 or row 1
        { 4, 5, 6 }, // Initializers for for indexed by 1 or row 2
        { 7, 8, 9 }, // Initializers for for indexed by 2 or row 3
        { 10, 11, 12 } // Initializers for for indexed by 3 or row 4
    };

    for (int i = 0; i < 4; i++);
    {
        for (int j = 0; j < 3; j++)
        {
            printf("Table [%d] [%d] = %d \n", i, j, table[i][j]);
        }
    }


    for (counter = 0; counter <= 2; counter++) {
        printf("Enter values for two sides: ");
        scanf("%lf %lf", &side1, &side2);

        printf("%.2f\n", hypotenuse(side1, side2, side3));
    }

    return 0;
}

double hypotenuse(double x, double y, double z) {
    x *= x;
    y *= y;
    z = sqrt(x + y);

    return z;
}

现在第26行有一个错误，我没有定义我，我不明白这不是因为第22行应该定义它，所以我想。

任何帮助将不胜感激！〜CRob

Answer 1

以下建议的代码：

干净地编译
正确检查（并处理）错误
格式化以提高用户可读性
产生所需的功能

现在，建议的代码：

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该程序的典型运行结果为：

#include <stdio.h>    // printf(), fprintf(), scanf()
#include <stdlib.h>   // exit(0, ESIT_FAILURE
//#include <string.h>
#include <math.h>     // sqrt()

#define ROWS 4
#define COLS 3
#define NUM_CALCULATIONS 3

double hypotenuse( double x, double y );

int main( void )
{

    double side1;
    double side2;

    int table[ ROWS ][ COLS ] =
    {
/* Column 0  1  2 */
        { 1, 2, 3 },    // Initializers for for indexed by 0 or row 1
        { 4, 5, 6 },    // Initializers for for indexed by 1 or row 2
        { 7, 8, 9 },    // Initializers for for indexed by 2 or row 3
        { 10, 11, 12 }  // Initializers for for indexed by 3 or row 4
    };

    // display table to user
    for (int i = 0; i < ROWS; i++)
    {
        for (int j = 0; j < COLS; j++)
        {
            printf("Table [%d] [%d] = %d \n", i, j, table[i][j]);
        }
        puts( "" );
    }

    // input triangle legs, then display hyp to user
    for ( size_t counter = 0; counter < NUM_CALCULATIONS; counter++) 
    {
        printf("Enter values for two sides: ");

        if( scanf( "%lf %lf", &side1, &side2 ) != 2 )
        {
            fprintf( stderr, "scanf failed to read the two user inputs, exiting\n" );
            exit( EXIT_FAILURE );
        }

        printf( "%.2f\n", hypotenuse( side1, side2 ) );
    }

    return 0;
}

double hypotenuse( double x, double y )
{
    x *= x;
    y *= y;
    return  sqrt(x + y);
}

使用C中的数组计算直角三角形的斜边

1 个答案: