Question

public void longestName(Scanner console, int num) {
    String longest = "";
    boolean tie = false;

    for(int i = 1; i <= num; i++) {
        System.out.print("name #" + i + "? " );
        String name = console.next();

        if(name.length() == longest.length()) {
            tie = true;
        } else if(name.length() > longest.length()) {
            tie = false;
            longest = name;
        }
    }

    String capitalized = longest.substring(0, 1).toUpperCase() +
                         longest.substring(1).toLowerCase();
    System.out.println(capitalized + "'s name is longest");

    if(tie)
        System.out.println("(There was a tie!)");
}}

if循环总是返回tie为true。如何检查最长名称的领带？

Answer 1

只有当多个名称具有相同字符并且最长时，if才会返回true。或者，领带是假的将您的代码更改为可运行的类，测试如下：

import java.util.Scanner;

public class Test {
    public static void main(String args[]){
        longestName(new Scanner(System.in), 3);
    }

    public static void longestName(Scanner console, int num) {

        String longest = "";

        boolean tie = false;

        for (int i = 1; i <= num; i++) {

            System.out.print("name #" + i + "? ");

            String name = console.next();

            if (name.length() == longest.length()) {

                tie = true;

            } else if (name.length() > longest.length()) {

                tie = false;

                longest = name;

            }

        }

        String capitalized = longest.substring(0, 1).toUpperCase() +

                longest.substring(1).toLowerCase();

        System.out.println(capitalized + "'s name is longest");

        if (tie)

            System.out.println("(There was a tie!)");
    }
}

输入是jordan，tom和bob，输出如下：

name #1? jordan
name #2? tom
name #3? bob
Jordan's name is longest

另一个测试是：

name #1? mary
name #2? andy
name #3? tom
Mary's name is longest
(There was a tie!)

在java中找到最长的名字

1 个答案: