我有一个boost套接字,我定义了一个异步接收:
Keywords_33=[('File_2', ['with', 'as']),
('Module_2', ['from', 'import']),
('Constant_3', {'bool': ['False', 'True'],
'none': ['None']}),
('Operator_4', {'boolean_operation': {'or', 'and', 'not'},
'comparison': {'is'}}),
('Container_operation_2', ['in', 'del']),
('Klass_1', ['class']),
('Function_7',['lambda', 'def', 'pass',
'global', 'nonlocal',
'return', 'yield']),
('Repetition_4', ['while', 'for', 'continue', 'break']),
('Condition_3', ['if', 'elif', 'else']),
('Debug_2', ['assert', 'raise']),
('Exception_3', ['try', 'except', 'finally'])]
kwlist = ['False', 'None', 'True', 'and', 'as', 'assert', 'break', 'class', 'continue', 'def',
'del', 'elif', 'else', 'except', 'finally', 'for', 'from', 'global', 'if', 'import',
'in','is', 'lambda', 'nonlocal', 'not', 'or', 'pass', 'raise', 'return', 'try', 'while',
'with', 'yield']
if __name__ == '__main__':
result = []
for kw in kwlist:
for key in Keywords_33:
if isinstance(key[1], list):
for i in key[1]:
if kw == i:
result.append(i)
elif isinstance(key[1], dict):
for value in key[1].values():
for j in value:
if kw == j:
result.append(j)
print(result)
但是如果没有事件进入这个套接字(套接字上没有数据包),我会陷入lambda方法......
有没有办法在这个recv上定义超时?
答案 0 :(得分:0)
有没有办法在这个recv上定义超时?
如果对Component::recv
的调用本身是asio
- 操作,您可以定义一个截止时间计时器,在超时时取消读取操作。您可以在Boost documentation中找到示例(示例/ cpp03 / timeouts / blocking_tcp_client.cpp)。
否则,您可以使用std :: future:
using namespace std::chrono_literals;
auto fut = std::async(std::launch::async, &Component::recv, handler);
if(fut.wait_for(500ms) == std::future_status::timeout) {
// timed out
}