Question

移动鼠标后，我有一组对角线。

如果我在页面上只有一个组实例但我需要有多个实例，这样可以正常工作。

当我复制HTML时，它们不能彼此独立地工作，并且不会产生所需的效果。

jQuery的：

var dash = $(".graphic-wave__dash");
if(dash.length > 0){
  var offset = dash.offset();
  function mouse(evt){
    var center_x = (offset.left) + (dash.width()/2);
    var center_y = (offset.top) + (dash.height()/2);
    var mouse_x = evt.pageX; var mouse_y = evt.pageY;
    var radians = Math.atan2(mouse_x - center_x, mouse_y - center_y);
    var degree = (radians * (180 / Math.PI) * -1) + 90;
    dash.css('-moz-transform', 'rotate('+degree+'deg)');
    dash.css('-webkit-transform', 'rotate('+degree+'deg)');
    dash.css('-o-transform', 'rotate('+degree+'deg)');
    dash.css('-ms-transform', 'rotate('+degree+'deg)');
    dash.removeClass('original');
  }
  $(document).mousemove(mouse);
}

HTML：

<div class="graphic-wave">
  <div class="graphic-wave__row">
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
  </div>
  <div class="graphic-wave__row">
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
  </div>
  <div class="graphic-wave__row">
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
  </div>
</div>

<div class="graphic-wave" style="left: 400px;">
  <div class="graphic-wave__row">
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
  </div>
  <div class="graphic-wave__row">
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
  </div>
  <div class="graphic-wave__row">
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
    <div class="graphic-wave__dash original"></div>
  </div>
</div>

https://jsfiddle.net/ob80/7nxf07vo/3/

有人可以帮忙吗？

Answer 1

您需要单独计算每一行的旋转，此时您正在计算单个旋转样式并将其应用于graphic-wave__dash类的每个元素。

Here's a quick example我还没有做过任何优化，这可能效率很低。（我没有把它放到一个片段中，因为它看起来并不支持SCSS）

var dash = $(".graphic-wave__dash");
if (dash.length > 0) {

  function mouse(evt) {
    dash.each(function() { // Calculate per element, not just once
      var offset = $(this).offset(); // Workout the offset per element
      var center_x = (offset.left) + ($(this).width() / 2); // Use $(this) to reference the current element
      var center_y = (offset.top) + ($(this).height() / 2);
      var mouse_x = evt.pageX;
      var mouse_y = evt.pageY;
      var radians = Math.atan2(mouse_x - center_x, mouse_y - center_y);
      var degree = (radians * (180 / Math.PI) * -1) + 90;
      $(this).css('-moz-transform', 'rotate(' + degree + 'deg)');
      $(this).css('-webkit-transform', 'rotate(' + degree + 'deg)');
      $(this).css('-o-transform', 'rotate(' + degree + 'deg)');
      $(this).css('-ms-transform', 'rotate(' + degree + 'deg)');
      $(this).removeClass('original');
    });
  }
  $(document).mousemove(mouse);
}

所做的更改是：

在函数内部，使用类
计算每个元素的偏移量，而不是全部基于该类的第一个实例

Answer 2

我将所有项目的center_x和center_y设置为属性，从而提高了DBS answer的效果，因此无需每次都计算：

var dash = $(".graphic-wave__dash");
if (dash.length > 0) {

    dash.each(function() {
      var offset = $(this).offset();
      $(this).attr('center_x',(offset.left) + ($(this).width() / 2));
      $(this).attr('center_y',(offset.top) + ($(this).height() / 2));
  });

  function mouse(evt) {
    dash.each(function() {
      var mouse_x = evt.pageX;
      var mouse_y = evt.pageY;
      var radians = Math.atan2(mouse_x - $(this).attr('center_x'), mouse_y - $(this).attr('center_y'));
      var degree = (radians * (180 / Math.PI) * -1) + 90;
      $(this).css('-moz-transform', 'rotate(' + degree + 'deg)');
      $(this).css('-webkit-transform', 'rotate(' + degree + 'deg)');
      $(this).css('-o-transform', 'rotate(' + degree + 'deg)');
      $(this).css('-ms-transform', 'rotate(' + degree + 'deg)');
      $(this).removeClass('original');
    });
  }
  $(document).mousemove(mouse);
}

这是小提琴：https://jsfiddle.net/7nxf07vo/6/

在mousemove上旋转多组形状

2 个答案: