Question

我正在弄清楚如何打平比赛。我遇到了困难。任何人都可以提供代码来替换它或修复它吗？谢谢。

我在python中编写了一个tic tac toe游戏，它完美无缺。所以我想知道，你能以某种方式对游戏进行编程说，＆＃34;你想再玩一次吗？＆＃34;电脑赢了之后还是赢了？

在我的游戏中，一旦计算机获胜或者你赢了，它就不会说什么，我希望游戏能够询问玩家是否想再玩一次。

谢谢。

import os
import time
import random

# Define the board
board = [" ", " ", " ", " ", " ", " ", " ", " ", " ", " "]


# Print the header
def print_header():
    print("""                                                                         
 _____  _  ____     _____  ____  ____     _____  ____  _____                 _________   _______   _______   
/__ __\/ \/   _\   /__ __\/  _ \/   _\   /__ __\/  _ \/  __/    1 | 2 | 3    |___    /  |      /  |  ____|
  / \  | ||  / _____ / \  | / \||  / _____ / \  | / \||  \      4 | 5 | 6      /   /    |   _/    | |   ___ 
  | |  | ||  \_\____\| |  | |-|||  \_\____\| |  | \_/||  /_     7 | 8 | 9    /   /____  |     \   | |___\ |
  \_/  \_/\____/     \_/  \_/ \|\____/     \_/  \____/\____\                 |_______|  |______|  |_______|

 To play Tic-Tac-Toe, you need to get three in a row...
 Your choices are defined, they must be from 1 to 9...

""")


def print_board():
    print('    |    |    ')
    print("  " + board[1] + " | " + board[2] + "  | " + board[3] + "  ")
    print("    |    |    ")
    print("----|----|----")
    print("    |    |    ")
    print("  " + board[4] + " | " + board[5] + "  | " + board[6] + "  ")
    print("    |    |    ")
    print("----|----|----")
    print("    |    |    ")
    print("  " + board[7] + " | " + board[8] + "  | " + board[9] + "  ")
    print("    |    |    ")


def is_winner(board, player):
    if (board[1] == player and board[2] == player and board[3] == player) or \
            (board[4] == player and board[5] == player and board[6] == player) or \
            (board[7] == player and board[8] == player and board[9] == player) or \
            (board[1] == player and board[4] == player and board[7] == player) or \
            (board[2] == player and board[5] == player and board[8] == player) or \
            (board[3] == player and board[6] == player and board[9] == player) or \
            (board[1] == player and board[5] == player and board[9] == player) or \
            (board[3] == player and board[5] == player and board[7] == player):
        return True
    else:
        return False


def is_board_full(board):
    count = 0
    for a in range(9):
        if board[a] == "X" or board[a] == "O":
            count += 1
            return False
        if count == 9:
            print("The game ends in a Tie\n")
            return True


while True:
    os.system("clear")
    print_header()
    print_board()

    choice = input("Please choose an empty space for X. ")
    choice = int(choice)

    if board[choice] == " ":
        board[choice] = "X"
    else:
        print("Sorry, that space has been checked!")
        time.sleep(1)

    if is_winner(board, "X"):
        os.system("clear")
        print_header()
        print_board()
        print("X wins! Congratulations")
        break

    os.system("clear")
    print_header()
    print_board()

    if is_board_full(board):
        print("Tie!")
        break

    choice = input("Please choose an empty space for O.")
    choice = int(choice)

    if board[choice] == " ":
        board[choice] = "O"

    else:
        print("Sorry, that space has been checked!")
        time.sleep(1)

    if is_winner(board, "O"):
        os.system("clear")
        print_header()
        print_board()
        print("O win! Congratulations")
        break

Answer 1

在您的＆＃34; tie＆＃34;中发现了问题。码。问题在于is_board_full函数。这对我有用：

def is_board_full(board):
    count = 0
    for a in range(1,10):
        if board[a] == "X" or board[a] == "O":
            count += 1
    if count == 9:
        print("The game ends in a Tie\n")
        return True
    return False

问题是您将电路板从索引1设置为9.范围（9）返回数字0到8，因此您永远不会检查最后一个单元格。另外，不确定为什么你把＆＃34;返回false＆＃34;在那里发表声明。

现在询问用户是否想要其他游戏，只需更改while条件以检查变量，让我们称之为“＃34; play＆＃34;游戏结束后，只需添加此代码或类似内容：

play = False
var = raw_input("If you want to play again press 'y'. If not press any other key.")
if var == 'y':
    play = True

确保将其添加为一个函数，并在代码中游戏结束的每个地方使用它。

详细了解Reading input in Python

我怎么能＆＃34; TIE＆＃34;在我的python TIC TAC TOE游戏中

1 个答案: