Question

我正在使用Open Weather Map API来获取用户当前的天气。

当我在Postman中运行请求时，我得到状态代码200并且能够接收数据。但是，在Xcode中我收到错误-1002

以下是执行'GET'请求的代码：

// Configure URL String
NSString *apiKey = @"MY_API_KEY";
NSString *urlString = [[NSString alloc] initWithFormat:@"api.openweathermap.org/data/2.5/weather?APPID=%@&lat=%@&lon=%@", apiKey, latitude, longitude]; 
NSString *encodedUrl = [urlString stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLQueryAllowedCharacterSet]];
NSURL *url = [NSURL URLWithString:encodedUrl];
NSMutableURLRequest *theRequest = [NSMutableURLRequest requestWithURL:url];

[theRequest setHTTPMethod:@"GET"];

NSURLSession *session = [NSURLSession sessionWithConfiguration:[NSURLSessionConfiguration defaultSessionConfiguration]];

[[session dataTaskWithRequest:theRequest completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
    if(data != nil) {
        NSDictionary *jsonDict = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:&error];
        NSLog(@"Here is the json dict: %@", jsonDict);
        NSLog(@"%@", response);
    }
    else {
        NSLog(@"error: %@", error);
    }
}] resume];

同样，这里的请求会返回错误但在Postman中我运行时没有错误：

api.openweathermap.org/data/2.5/weather?APPID=MY_API_KEY&lat=33.712926&lon=-117.839181

我如何设置请求有什么问题？

Answer 1

URL需要方案部分。请确保在您的网址字符串中添加http或https等协议：

NSString *urlString = [[NSString alloc] initWithFormat:@"https://api.openweathermap.org/data/2.5/weather?APPID=%@&lat=%@&lon=%@", apiKey, latitude, longitude];

NSMutableURLRequest不支持的URL

1 个答案: