Question

您好请帮我解决如何为api

准备NSMutableURLRequest

网址：www.XXXXXXXX.com/api.php

登录： -

www.XXXXXXXXXXXX.com/api.php?task=login

POST数据： -

“email”=＆gt;用户的电子邮件

“pw”=＆gt;用户密码

json响应：成功登录时的会话ID

我是这样想的。

NSMutableURLRequest *request;

request=[NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"www.XXXXXXXX.com/api.php?task=login"]];


[request setHTTPMethod:@"POST"];


NSString *postString =@"email=xxxxxxxx@gmail.com&pw=1234";

[request setValue:[NSString
                   stringWithFormat:@"%d", [postString length]] forHTTPHeaderField:@"Content-length"];

[request setHTTPBody:[postString
                      dataUsingEncoding:NSUTF8StringEncoding]];

NSURLConnection *connection=[[NSURLConnection alloc] initWithRequest:request delegate:self];

Answer 1

一个原因可能是您忘记添加“http：”方案：

[NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://www.XXXXXXXX.com/api.php?task=login]];
                                                     HERE --^

另请注意，设置正文数据的正确方法，尤其是长度

NSString *postString =@"email=xxxxxxxx@gmail.com&pw=1234";
NSData *postData = [postString dataUsingEncoding:NSUTF8StringEncoding];
[request setValue:[NSString stringWithFormat:@"%d", [postData length]]
              forHTTPHeaderField:@"Content-length"];
[request setHTTPBody:postData];

因为UTF-8编码数据的长度可能与（Unicode）字符串长度不同。

Answer 2

试试这个：

NSError *error;
NSString *jsonString;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:jsonData1
                                                   options:0 error:&error];

if (!jsonData) {
    NSLog(@"Got an error: %@", error);
} else {
    jsonString= [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
}

NSData *postData = [[[NSString alloc] initWithFormat:@"method=methodName&email=%@&password=%@", user_name, pass_word] dataUsingEncoding:NSUTF8StringEncoding];
NSString *postLength = [NSString stringWithFormat:@"%ld",[postData length]];

jsonData=[jsonString dataUsingEncoding:NSUTF8StringEncoding];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:URL]];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"\"Accept\""];
[request setValue:@"application/json" forHTTPHeaderField:@"\"Content-Type\""];
[request setValue:postLength forHTTPHeaderField:@"\"Content-Length\""];
[request setValue:@"application/x-www-form-urlencoded; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:jsonData];
NSError *requestError = [[NSError alloc] init];
NSHTTPURLResponse *response = nil;
NSData *urlData = [NSURLConnection sendSynchronousRequest:request
                                        returningResponse:&response
                                                    error:&requestError];

if ([response statusCode] >= 200 && [response statusCode] < 300) {
    NSError *serializeError = nil;

    NSString* newStr = [NSString stringWithUTF8String:[urlData bytes]];

    NSDictionary *jsonData = [NSJSONSerialization
                              JSONObjectWithData:urlData
                              options:NSJSONReadingAllowFragments
                              error:&serializeError];
     NSLog(@"recdata %@",jsonData);
}
NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];

if (connection)
{
    NSLog(@"theConnection is succesful");
}
[connection start];

Answer 3

当我使用一个意外包含新行的变量指定我的基本URL时，我遇到了这个错误。

不支持的URL错误代码-1002

3 个答案: