Question

大家好我以前知道这个问题，但我没有从他们那里得到任何解决方案在我的项目中，我在登录视图中工作，当我将代码放在登录按钮上时，我收到错误

错误：错误域= NSURLErrorDomain代码= -1002“不支持的URL” UserInfo = 0x7fb37b62c9a0 {NSLocalizedDescription =不支持的URL， NSUnderlyingError = 0x7fb37b715a20“操作无法完成。（kCFErrorDomainCFNetwork错误-1002。）“}

但我使用相同的登录代码，我在以前的项目中使用它并且它在那里工作正常

这是我的代码：

-(IBAction)login:(id)sender
{
    NSURLSessionConfiguration *configuration = [NSURLSessionConfiguration defaultSessionConfiguration];
    NSURLSession *session = [NSURLSession sessionWithConfiguration:configuration delegate:self delegateQueue:nil];
    NSURL *url = [NSURL URLWithString:@"http://eyeforweb.info.bh-in-15.webhostbox.net/myconnect/api.php?token={LS0tLS1CRUdJTiBQVUJMSUMgS0VZLS0tLS0KTUc4d0RRWUpLb1pJaHZjTkFRRUJCUUFEWGdBd1d3SlVBeWo0WE9JNjI4cnJRTG9YeEpXNG1zUWI1YmtvYk1hVQpzMnY1WjFKeXJDRWdpOVhoRzZlZk4rYTR0eGlMTVdaRXdNaS9uS1cyL1NCS2pCUnBYUzVGYUdiV0VLRG1WOXkvCkYrWHhsUXVoeER0MEV3YkRBZ01CQUFFPQotLS0tLUVORCBQVUJMSUMgS0VZLS0tLS0K}&method=user.getLogin"];
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
                                                           cachePolicy:NSURLRequestUseProtocolCachePolicy
                                                       timeoutInterval:60.0];

    [request addValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
    [request addValue:@"*/*" forHTTPHeaderField:@"Accept"];
    [request setHTTPMethod:@"POST"];
    NSString *mapData = [NSString stringWithFormat:@"login=abc@gmail.com&password=123456"];//,username.text, password.text];
    NSData *postData = [mapData dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
    [request setHTTPBody:postData];
    NSLog(@"map data is = %@",mapData);
    NSURLSessionDataTask * postDataTask = [session dataTaskWithRequest:request completionHandler:^(NSData * data, NSURLResponse* response, NSError * error) {

        if(error == nil)
        {
            NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
            NSString *text = [[NSString alloc] initWithData: data encoding: NSUTF8StringEncoding];
            NSLog(@"Data = %@",text);
            NSDictionary *jsonDic = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
            NSLog(@"jsondic= %@",jsonDic);

            NSDictionary *userDataDic = [jsonDic objectForKey:@"data"];
            NSLog(@"Dict is %@",userDataDic);

请帮我解决一下我已经看到类似的问题，但没有克服这个问题任何帮助表示赞赏

Answer 1

我尝试了你的代码。除了你的网址，其他代码行是正确的。如果你传递了你的corrct网址，它就能完美运行。

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://eyeforweb.info.bh-in-15.webhostbox.net/myconnect/api.php"]]; //pass your url here
 [request setHTTPMethod:@"POST"];
 //Passing The String to server
 NSString *strUserId = @"pradeep.kumar@eyeforweb.com";
 NSString *strPassword = @"admin123";


 NSString *userUpdate =[NSString stringWithFormat:@"login=%@&password=%@",strUserId,strPassword, nil];

 //Check The Value what we passed
 NSLog(@"the data Details is %@", userUpdate);


 //Convert the String to Data
 NSData *data1 = [userUpdate dataUsingEncoding:NSUTF8StringEncoding];
 NSLog(@"The postData is - %@",data1);


 //Apply the data to the body
 [request setHTTPBody:data1];

 NSURLSession *session = [NSURLSession sharedSession];
 NSURLSessionDataTask *dataTask = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
 NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *)response;
 if(httpResponse.statusCode == 200)
 {
 NSError *parseError = nil;
 NSDictionary *responseDictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:&parseError];
 NSLog(@"The response is - %@",responseDictionary);
 NSInteger success = [[responseDictionary objectForKey:@"success"] integerValue];
 if(success == 1)
 {
 NSLog(@"Login SUCCESS");
 }
 else
 {
 NSLog(@"Login FAILURE");
 }
 }
 else
 {
 NSLog(@"Error");
 }
 }];
 [dataTask resume];

IOS：kCFErrorDomainCFNetwork错误-1002。错误域= NSURLErrorDomain代码= -1002“不支持的URL”

1 个答案: