网址申请表

时间:2010-11-25 15:04:33

标签: iphone nsmutableurlrequest

我有这个html表单将我的数据从iphone传递到Web服务器.. 但我已经陷入困境,如何将这个表单/数据构建成一个可变的请求。你能来吗?建议我。

Html表格:

<html>
<form method="post" action="https://mysite.com"> 
<input type="hidden" name="action" value="sale"> 
<input type="hidden" name="acctid" value="TEST123"> 
<input type="hidden" name="amount" value="1.00">
<input type="hidden" name="name" value="Joe Customer"> 
<input type="submit"> 
</form>
</html>

我不知道如何在url请求中为特定键分配“值”(例如action,acctid,amount,name)???

这是我的代码:

NSString *urlString =  @"https://mysite.com";
NSMutableURLRequest *urlRequest = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:urlString]];

NSString *post = [[NSString alloc] initWithFormat:@"%@%@&%@%@&%@%@&%@%@", 
   action, sale, 
   acctid, TEST123, 
   amount, 1.00,
                                      name, Joe Customer];  // ????

NSData *postData = [post dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES];    
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];  

[urlRequest setHTTPMethod:@"POST"];  
[urlRequest setValue:postLength forHTTPHeaderField:@"Content-Length"];  
[urlRequest setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];  // multipart/form-data
[urlRequest setHTTPBody:postData];

1 个答案:

答案 0 :(得分:3)

看起来是正确的,虽然你的格式字符串中缺少一些等号,你需要在@""中包装你的字符串参数:

NSString *post = [[NSString alloc] initWithFormat:@"%@=%@&%@=%@&%@=%@&%@=%@", 
    @"action", @"sale", 
    @"acctid", @"TEST123", 
    @"amount", @"1.00",
    @"name", @"Joe Customer"];

对于更可扩展的解决方案,您可以将键/值对存储在字典中,然后执行以下操作:

// Assuming the key/value pairs are in an NSDictionary called payload

NSMutableString *temp = [NSMutableString stringWithString:@""];
NSEnumerator *keyEnumerator = [payload keyEnumerator];
id key;
while (key = [keyEnumerator nextObject]) {
    [temp appendString:[NSString stringWithFormat:@"%@=%@&", 
        [key description], 
        [[payload objectForKey:key] description]]];
}
NSString *httpBody = [temp stringByTrimmingCharactersInSet:
    [NSCharacterSet characterSetWithCharactersInString:@"&"]];

(请记住,您可能需要对键和值进行URL编码。)