我正在尝试编写一个脚本,用户在该脚本中插入月收入,并在30年后获得复合利息的未来值。就像现在一样,我已经为测试目的分配了一些值。
// Future Value
var investment = 800;
var annualRate = 2;
var monthlyRate = annualRate / 12 / 100;
var years = 30;
var months = years * 12;
var futureValue = 0;
for ( i = 1; i <= months; i++ ) {
futureValue = futureValue + investment * Math.pow(1 + monthlyRate, months);
}
问题是,我实际上是从使用内置FV()公式的Excel电子表格构建这个,并且在交叉检查时,我的结果完全关闭......任何想法我做错了,因为我'我根本没有进入金融数学。提前谢谢。
答案 0 :(得分:8)
Math.pow
是不必要的,因为您逐月计算并递增futureValue
。只需乘以1 + monthlyRate
即可。您还希望在乘以之前将投资的当前值添加到新投资中:
for ( i = 1; i <= months; i++ ) {
futureValue = (futureValue + investment) * (1 + monthlyRate);
}
或者,您也可以使用以下公式一次性计算:
futureValue = investment * (Math.pow(1 + monthlyRate, months) - 1) / monthlyRate;
答案 1 :(得分:2)
下面是计算复利的代码。
function calculate() {
p = document.getElementById("p").value;
n = document.getElementById("n").value; // no. of compoundings per year
t = document.getElementById("t").value; // no. of years
r = document.getElementById("r").value;
result = document.getElementById("result");
// The equation is A = p * [[1 + (r/n)] ^ nt]
A = (p * Math.pow((1 + (r / (n * 100))), (n * t)));
// toFixed is used for rounding the amount with two decimal places.
result.innerHTML = "The total amount is " + A.toFixed(2);
result.innerHTML += "<br> The interest is " + (A.toFixed(2) - p).toFixed(2);
}
div {
display: table-row;
}
label,
input {
display: table-cell;
}
<html>
<head>
<title>Compound Interest Calculation using jquery</title>
</head>
<body>
<h1>Compound Interest Calculation Using JQery</h1>
<div> <label>Amount: </label> <input id="p"> </div>
<div> <label>Rate (%): </label> <input id="r"> </div>
<div> <label>No. of Years: </label> <input id="t"> </div>
<div> <label>Compunding Times Per Year: </label> <input id="n" value="1"> </div>
<button onclick="calculate()">Calculate</button>
<p id="result"></p>
</body>
</html>
答案 2 :(得分:0)
function FVcalc(PresentAmount,InterestRate,NumberOfYears) {
var timescompound = 1;
var AnnualInterestRate = (InterestRate/100)/timescompound;
var Years= NumberOfYears
var Periods=timescompound*Years;
var NumPayments=Periods;
var Prin=PresentAmount;
MonthPayment=Math.floor((Prin)*(Math.pow((1+AnnualInterestRate),(Periods)))*100)/100;
FVFactor=(Math.pow((1+AnnualInterestRate),(Periods)))
return MonthPayment
}
答案 3 :(得分:0)
这是我编写复利的代码
function call()
{
var A = Principle;
var B = Interest;
var C = Years;
var D = 0;
var E = A*B/100;
D+=E;
var f=E+A;
document.write("0 year: Interest "+E+" Principal: "+f);
document.write("<br />");
for (var i=1; i<C; i++)
{
E=f*B/100;
D+=E;
f=E+f;
document.write(i+"year: Interest "+E+" Principal:"+f);
document.write("<br />");
}
return false;
}
答案 4 :(得分:0)
我也发现了这种替代方法:
function compoundInterest(principal, annual_rate, n_times, t_years) {
return principal*(Math.pow(1 + annual_rate/n_times, n_times*t_years) - 1);
}
答案 5 :(得分:0)
这在任何情况下都适用,请注意period
的基准是一年1次,例如每6个月period = 2
,4个月period = 3
等……>
var init = 500000
var years = 30
var compound = 1
var interest = 3.99
var period= 2
var total = 0
function CInterest(){
for(let i=0; i<years*12; i++){
if(i%(12/period) === 0){
compound*=(1+((interest/100)/period))
}
}
total= init*compound
}
CInterest()
console.log("total: ",total)