我正在尝试为课程编写一个简单的tic tac toe程序。我知道网站上有其他帖子回应类似的课程工作，但我找不到我需要的帮助。我为我的网格设置了一个二维数组。我有9个标签来保持随机生成的0或1代表X（1）或O（0）。我的问题是我不确定如何显示X或O而不是数字。另外，我有几行设置来检查X或O是否赢了，但是，我不知道如何显示它是否是平局。我不是在寻找直接的答案，而是指导如何实现这一目标。截至目前，我的表格将显示随机的1和0，如果符合条件将说明X或O是否赢了，但即使X或O没有获胜也会这样做。除了单击调用函数的按钮以生成数字并更新表单之外，此游戏没有人为因素。我的代码如下：
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace TicTacToe
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void playAgain_Click(object sender, EventArgs e)
{
Random rand = new Random();
const int rows = 3;
const int columns = 3;
int[,] board = new int[rows, columns];
for (int row = 0; row < rows; row++)
{
for (int col = 0; col < columns; col++)
{
board[row, col] = rand.Next(2);
}
}
square1.Text = board[0, 0].ToString();
square2.Text = board[0, 1].ToString();
square3.Text = board[0, 2].ToString();
square4.Text = board[1, 0].ToString();
square5.Text = board[1, 1].ToString();
square6.Text = board[1, 2].ToString();
square7.Text = board[2, 0].ToString();
square8.Text = board[2, 1].ToString();
square9.Text = board[2, 2].ToString();
//O win check
if (board[0,0] == 0 && (board[0,0] == board[0,1]) && (board[0,1] == board[0,2]))
{
winnerBox.Text = "O wins!";
}
else if (board[1, 0] == 0 && (board[1, 0] == board[1, 1]) && (board[1, 1] == board[1, 2]))
{
winnerBox.Text = "O wins!";
}
else if (board[2, 0] == 0 && (board[2, 0] == board[2, 1]) && (board[2, 1] == board[2, 2]))
{
winnerBox.Text = "O wins!";
}
else if (board[0, 0] == 0 && (board[0, 0] == board[1, 0]) && (board[1, 0] == board[2, 0]))
{
winnerBox.Text = "O wins!";
}
else if (board[0, 1] == 0 && (board[0, 1] == board[1, 1]) && (board[1, 1] == board[2, 1]))
{
winnerBox.Text = "O wins!";
}
else if (board[0, 2] == 0 && (board[0, 2] == board[1, 2]) && (board[1, 2] == board[2, 2]))
{
winnerBox.Text = "O wins!";
}
else if (board[0, 0] == 0 && (board[0, 0] == board[1, 1]) && (board[1, 1] == board[2, 2]))
{
winnerBox.Text = "O wins!";
}
else if (board[0, 2] == 0 && (board[0, 2] == board[1, 1]) && (board[0, 1] == board[2, 0]))
{
winnerBox.Text = "O wins!";
}
//X win check
if (board[0, 0] == 1 && (board[0, 0] == board[0, 1]) && (board[0, 1] == board[0, 2]))
{
winnerBox.Text = "X wins!";
}
else if (board[1, 0] == 1 && (board[1, 0] == board[1, 1]) && (board[1, 1] == board[1, 2]))
{
winnerBox.Text = "X wins!";
}
else if (board[2, 0] == 1 && (board[2, 0] == board[2, 1]) && (board[2, 1] == board[2, 2]))
{
winnerBox.Text = "X wins!";
}
else if (board[0, 0] == 1 && (board[0, 0] == board[1, 0]) && (board[1, 0] == board[2, 0]))
{
winnerBox.Text = "X wins!";
}
else if (board[0, 1] == 1 && (board[0, 1] == board[1, 1]) && (board[1, 1] == board[2, 1]))
{
winnerBox.Text = "X wins!";
}
else if (board[0, 2] == 1 && (board[0, 2] == board[1, 2]) && (board[1, 2] == board[2, 2]))
{
winnerBox.Text = "X wins!";
}
else if (board[0, 0] == 1 && (board[0, 0] == board[1, 1]) && (board[1, 1] == board[2, 2]))
{
winnerBox.Text = "X wins!";
}
else if (board[0, 2] == 1 && (board[0, 2] == board[1, 1]) && (board[0, 1] == board[2, 0]))
{
winnerBox.Text = "X wins!";
}
}
private void exitButton_Click(object sender, EventArgs e)
{
this.Close();
}
}
}
答案 0 :(得分：0)
试试这个：
private Random rand = new Random();
private void playAgain_Click(object sender, EventArgs e)
{
TextBox[][] squares = new TextBox[][]
{
new TextBox[] { square1, square2, square3 },
new TextBox[] { square4, square5, square6 },
new TextBox[] { square7, square8, square9 },
};
const int rows = 3;
const int columns = 3;
char[,] board = new char[rows, columns];
for (int row = 0; row < rows; row++)
{
for (int col = 0; col < columns; col++)
{
board[row, col] = rand.Next(2) == 0 ? 'O' : 'X';
squares[row][col].Text = board[row, col].ToString();
}
}
var scoring =
Enumerable
.Range(0, 3)
.SelectMany(n => new[]
{
Enumerable.Range(0, 3).Select(x => board[n, x]),
Enumerable.Range(0, 3).Select(x => board[x, n]),
})
.Concat(new[]
{
Enumerable.Range(0, 3).Select(x => board[x, x]),
Enumerable.Range(0, 3).Select(x => board[x, 2 - x]),
})
.Select(xs => String.Join("", xs))
.ToLookup(x => x);
int xwins = scoring["XXX"].Count();
int owins = scoring["OOO"].Count();
if (xwins == 1 & owins == 0)
{
winnerBox.Text = "X wins!";
}
else if (xwins == 0 && owins == 1)
{
winnerBox.Text = "O wins!";
}
else if (xwins == 0 && owins == 0)
{
winnerBox.Text = "Draw";
}
else
{
winnerBox.Text = "Invalid Game";
}
}
答案 1 :(得分：0)
以下是您想要的提示。
将纸板项目分配给标签文本时，将其转换为X或O：
square1.Text = board[0, 0] == 0 ? "O" : "X";
//In the check if O wins record the winning text in a string instead of winnerBox.Text.
string oWinsText == string.Empty;
if (board[0,0] == 0 && (board[0,0] == board[0,1]) && (board[0,1] == board[0,2])) {
oWinsText = "O wins!"; }
//Then do the same in the check if X wins:
string xWinsText == string.Empty;
if (board[0,0] == 0 && (board[0,0] == board[0,1]) && (board[0,1] == board[0,2])) {
xWinsText = "X wins!"; }
//Check if it's a draw:
bool isDraw = (oWinsText.Length > 0 && xWinsText.Length > 0);
//Finally show the result
if (isDraw)
winnerBox.Text = "Draw";
else
winnerBox.Text = oWinsText + xWinsText;