Question

我需要从wav的音频数据中间提取 8秒。文件与长度0:27秒。

- 所有我已经做过的事情，中间的9秒分为wav。在3个部分上文件并取中间部分，但它是9s我需要8s。

如何在numpy数组中找到位数？

import scipy.io.wavfile import pyaudio import numpy as np (samplRate,data)=scipy.io.wavfile.read('Track48.wav') print CHANNELS=2 p= pyaudio.PyAudio() # nine_sec=len(data)/3 eight_sec=2*len(data)/3 stream = p.open(format=pyaudio.paInt16, channels=CHANNELS, rate=44100, output=True ) cuted_data=data[nine_sec:eight_sec] newdata = cuted_data.astype(np.int16).tostring() stream.write(newdata) print(cuted_data)

感谢您的帮助。

Answer 1

您可以非常轻松地使用pydub切片中间8秒。有关pydub are here的详情您可以安装为pip install pydub

我有一个持续时间为348秒的wav文件，中间8秒被切成薄片。

>>> song.duration_seconds
348.05551020408166

您还可以使用不同的文件格式，例如wav，mp3，m4a，ogg等进行导入（转换为数据段）和导出。

源代码

from pydub import AudioSegment
from pydub.playback import play

song = AudioSegment.from_wav("music.wav")

#slice middle eight seconds of audio
midpoint = song.duration_seconds // 2

left_four_seconds = (midpoint - 4) * 1000 #pydub workds in milliseconds
right_four_seconds = (midpoint + 4) * 1000 #pydub workds in milliseconds

eight_sec_slice = song[left_four_seconds:right_four_seconds ]

#Play slice
play(eight_sec_slice )

#or save to file
eight_sec_slice.export("eight_sec_slice.wav", format="wav")

正如您所见，中间8秒切片的长度完全符合要求。

>>> eight_sec_slice.duration_seconds
8.0

Answer 2

我知道这个问题很旧，但是有人可能喜欢我想提供的仅使用numpy的解决方案。不需要pydub。

import scipy.io.wavfile as wavfile

fs, data - wavefile.read("Track48.wav")

# number of samples N
N = data.shape[0]

# Convert seconds to samples
eight_secs_in_samples = float(fs)*8 # time = number_of_samples / rate

midpoint_sample = N//2 # Midpoint of sample

# substract 4 seconds from midpoint
left_side = midpoint_sample-(eight_secs_in_samples//2) 

# Add 4 seconds from midpoint up
right_side = midpoint_sample + (eight_secs_in_samples//2)

# The midpoint of samples is therefore:
mid8secs = array_data[int(left_side):int(right_side)] # this range contains the required samples
# Save the file
wavfile.write("eightSecSlice.wav",fs,mid8secs)

如何从wav中间时间范围。蟒

2 个答案: