在finally块中意识到异常，但没有catch块

Question

是否可以确定是否在没有catch块的情况下抛出了异常？ Visual Studio能够从我的程序状态中挖掘异常并将其作为伪变量（$ exception）。我可以做类似的事情吗？

我正在使用外部库，我无法在那里修改try-finally块。

以下是示例代码：

class Program
{
    static void Main()
    {
        TaskScheduler.UnobservedTaskException += (sender, args) =>
        {
            Console.WriteLine("UnobservedTaskException"); // this is never printed out
        };
        // <external>
        // this is simplified code of referenced library, I can't change this
        Task.Run(async () =>
        {
            try
            {
                BeforeExecute();
                await Execute(); // the library uses reflection to get the proper method dynamically, this is just simplification
            }
            finally
            {
                AfterExecute();
            }
        });
        // exception is never rethrown, because the library isn't (a)waiting the task here :(
        // </external>
        Console.ReadKey(true);
    }
    static void BeforeExecute()
    {
        // I use inheritance for this method, so I have to change it in just one place
        Console.WriteLine("BeforeExecute");
    }
    static void AfterExecute()
    {
        // I use inheritance for this method, so I have to change it in just one place
        Console.WriteLine("AfterExecute");
        // >>> can I have knowledge of the exception here? <<<
    }
    static Task Execute()
    {
        // I have multiple methods like this one, modifying this would be too much work
        Console.WriteLine("Execute");
        throw new Exception(); // the exception ends in abyss :(
    }
}