在Python中为列表中的每个字符串分配值

Question

我正在尝试生成一个随机数，然后将该值分配给列表中的某一天。

我想要发生的是，如果选择的值是“0”，我想打印一次SUNDAY（0 + 1次）。如果它的“1”我想要它打印SUNDAY（然后是下一行）MONDAYMONDAY（1 + 1次），依此类推。请参阅此图片以获取完整示例。

更新

此代码已经尝试过：

import random 
Random = random.randint(0, 6) 
dayList = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'] 
for dayList in Random(0): 
    print "Sunday" * 2

Answer 1

这是满足要求的代码：

import random 

dayList = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'] 

def day_of_week(value):
    return dayList[value] * (value + 1)

def print_script(value):
    print('The number is', value)
    for v in range(value + 1):
        print(day_of_week(v))

value = random.randint(0, 6)

print_script(value)

只是为了测试所有可能性：

for v in range(7): 
    print_script(v)

输出：

The number is 0
Sunday
The number is 1
Sunday
MondayMonday
The number is 2
Sunday
MondayMonday
TuesdayTuesdayTuesday
The number is 3
Sunday
MondayMonday
TuesdayTuesdayTuesday
WednesdayWednesdayWednesdayWednesday
The number is 4
Sunday
MondayMonday
TuesdayTuesdayTuesday
WednesdayWednesdayWednesdayWednesday
ThursdayThursdayThursdayThursdayThursday
The number is 5
Sunday
MondayMonday
TuesdayTuesdayTuesday
WednesdayWednesdayWednesdayWednesday
ThursdayThursdayThursdayThursdayThursday
FridayFridayFridayFridayFridayFriday
The number is 6
Sunday
MondayMonday
TuesdayTuesdayTuesday
WednesdayWednesdayWednesdayWednesday
ThursdayThursdayThursdayThursdayThursday
FridayFridayFridayFridayFridayFriday
SaturdaySaturdaySaturdaySaturdaySaturdaySaturdaySaturday