Question

当我在终端上运行时，此cURL命令正常工作：

curl -X POST -H“Content-Type：application / json”-H“授权：基本uname：pass123“-d'{”userName“：”uname“，”password“：”pass123“}' “http://mysite123.com/api/Login”

现在，我正在尝试使用Android Volley发送此帖子请求。代码如下：

RequestQueue queue = Volley.newRequestQueue(getApplicationContext());
    String url = "http://mysite123.com/api/Login";
    StringRequest stringRequest = new StringRequest(Request.Method.POST, url,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {

                    Toast.makeText(MainActivity.this,response,Toast.LENGTH_LONG).show();
                }
            },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {
                    Toast.makeText(MainActivity.this,error.toString(),Toast.LENGTH_LONG).show();
                    error.printStackTrace();
                }
            }){
        @Override
        protected Map<String,String> getParams(){

            Map<String,String> params = new HashMap<String, String>();
            params.put("userName", "uname");
            params.put("password", "pass123");
            return params;
        }
        @Override
        public Map<String, String> getHeaders() throws AuthFailureError {
            Map<String,String> headers=new HashMap<String,String>();

            headers.put("Content-Type", "application/json");
            headers.put("Accept", "application/json");
            headers.put("Accept-Encoding", "utf-8");
            String creds = String.format("%s:%s","uname","pass123");
            String auth = "Basic " + Base64.encodeToString(creds.getBytes(), Base64.NO_WRAP);
            headers.put("Authorization", auth );
            return headers;
        }

    };
    queue.add(stringRequest);

但它在stackTrace中给出了错误：

09-03 07：46：43.823 17712-17918 / com.ankitshubham97.gpsmonitoring E / Volley：[108117] BasicNetwork.performRequest：http://mysite123.com/api/Login的意外响应代码400 09-03 07：46：43.833 17712-17712 / com.ankitshubham97.gpsmonitoring E / Qmage：isQIO：stream不是QIO文件 09-03 07：46：43.843 17712-17712 / com.ankitshubham97.gpsmonitoring W / System.err：com.android.volley.ServerError 09-03 07:46:43.853 17712-17712 / com.ankitshubham97.gpsmonitoring W / System.err：at com.android.volley.toolbox.BasicNetwork.performRequest（BasicNetwork.java:163） 09-03 07：46：43.853 17712-17712 / com.ankitshubham97.gpsmonitoring W / System.err：at com.android.volley.NetworkDispatcher.run（NetworkDispatcher.java:112)<

可能是什么问题？或者从android直接发送curl命令的任何方法？

编辑：我甚至使用https://incarnate.github.io/curl-to-php/将上面的cURL命令转换为php代码，php也运行正常。我想知道Volley出了什么问题！

Answer 1

使用邮递员帮助了我。因此，问题是'{"userName":"uname","password":"pass123"}'将以json格式和正文（而不是param）作为原始表单发送。所以，我用这个方法：

            @Override
            public byte[] getBody() throws AuthFailureError {
                try {
                    return requestBody == null ? null : requestBody.getBytes("utf-8");
                } catch (UnsupportedEncodingException uee) {
                    VolleyLog.wtf("Unsupported Encoding while trying to get the bytes of %s using %s", requestBody, "utf-8");
                    return null;
                }
            }
            @Override
            public String getBodyContentType() {
                return "application/json";
            }

我之前将requestBody定义为：

JSONObject jsonBody = new JSONObject();
    try{

        jsonBody.put("userName", "uname");
        jsonBody.put("password", "pass123");
    }
    catch (JSONException e){

    }

    final String requestBody = jsonBody.toString();

发布请求在cURL中正常工作但在Android Volley

1 个答案: