Volley安卓库发布请求无效

时间:2016-02-15 11:32:48

标签: android android-volley

我知道有类似的问题,但我搜索了很多问题,但他们似乎并不适合我。所以我想做的是发送一个带有简单字符串"ON"/ "OFF"的发布请求作为数据。像这样的东西(对于一些$ URL):

curl -X POST --header "Content-Type: text/plain; charset=utf-8"  -d "ON" "$URL"

以下是我正在尝试的代码,在阅读了大量代码和答案后,我认为它会起作用,但事实并非如此。

我错过了什么?我从服务器获得400 error

Request request = new StringRequest
                    (Request.Method.POST, url,
                            new Response.Listener<String>() {
                                @Override
                                public void onResponse(String response) {
                                    Log.d(TAG, "Command was sent successfully");
                                }},
                            new Response.ErrorListener() {
                                @Override
                                public void onErrorResponse(VolleyError error) {
                                    Log.e(TAG, "Got command error for " + url + " command " + command + " error " + error.getMessage());
                                }
                            }) {
                @Override
                public Map<String, String> getHeaders() throws AuthFailureError {
                    Map<String, String> headers = new HashMap<String, String>();
                    headers.put("Content-Type", "text/plain; charset=utf-8");
                 //   headers.put("Accept", "application/json");
                 //   headers.put("User-agent", "My useragent");
                    return headers;
                }
                @Override
                public byte[] getBody() throws AuthFailureError {
                    try {
                        return command.getBytes("utf-8");
                    } catch (Exception e) {
                        Log.d(TAG, "failed converting" + e.getMessage());
                        return null;
                    }
                }
            };

1 个答案:

答案 0 :(得分:1)

您必须覆盖getParams()

@Override
protected Map<String, String> getParams() throws com.android.volley.AuthFailureError {  

    Map<String, String> params = new HashMap<String, String>();  
    params.put("postData", "my simple on/off string");  
    return params;  

};