Question

的问题

我认为下面会导致死锁，因为他们将id 1,2和3锁定在一个圆圈内。

- 交易1

UPDATE season_end_date SET ... WHERE id = 1
UPDATE season_end_date SET ... WHERE id = 2

- 交易2

UPDATE season_end_date SET ... WHERE id = 2
UPDATE season_end_date SET ... WHERE id = 3

- 交易3

UPDATE season_end_date SET ... WHERE id = 3
UPDATE season_end_date SET ... WHERE id = 1

但是，如果我按ID订购更新怎么办，那就像是：

- 交易1

UPDATE season_end_date SET ... WHERE id = 1
UPDATE season_end_date SET ... WHERE id = 2

- 交易2

UPDATE season_end_date SET ... WHERE id = 2
UPDATE season_end_date SET ... WHERE id = 3

- 交易3

UPDATE season_end_date SET ... WHERE id = 1
UPDATE season_end_date SET ... WHERE id = 3

这会解决死锁问题吗？我想是这样，因为T3现在应该能够运行，之后，T2可以运行，最后一个T1。