我有两个来自两个不同查询的相同键的数组。
首先查询结果:
Array
(
[0] => Array
(
[Contribution] => 1000.00
[P_Name] => A
)
[1] => Array
(
[Contribution] => 1500.00
[P_Name] => B
)
)
第二个查询结果:
Array
(
[0] => Array
(
[Contribution] => 100.00
[P_Name] => A
)
[1] => Array
(
[Contribution] => 200.00
[P_Name] => B
)
)
第一个数组可能为空,和/或第二个数组可能为空。
我想创建一个新数组,找到Contribution
值匹配的P_Name
值之和,如下所示:
Array
(
[0] => Array
(
[Contribution] => 1100.00
[P_Name] => A
)
[1] => Array
(
[Contribution] => 1700.00
[P_Name] => B
)
)
我试过array_merge()
:
$result1= $this->model1->getOthersTotal($date);
$result2=$this->model1->getMiscTotal($date);
$merged_result = array_merge( $result1, $result2 );
$merged_result
包含:
Array (
[0] => Array (
[Contribution] => 1000.00
[P_Name] => A
)
[1] => Array (
[Contribution] => 1001.00
[P_Name] => A
)
[2] => Array (
[Contribution] => 69.00
[P_Name] => B
)
)
答案 0 :(得分:1)
这是一种快速而又脏的方法:在两个数组上循环,外部循环填充内部循环。如果没有匹配的是fount,$ x将重新生成0,并且该值将被添加到内部循环中。如果找到匹配项,$ x为1,内循环将中断以继续外循环。
$a = [['a' => 10,'b' => 'g'], ['a' => 11,'b' => 'h']];
$b = [['a' => 1, 'b' => 'g'], ['a' => 2, 'b' => 'h'], ['a' => 3, 'b' => 'i']];
// now its fool proof.
function mergeData( $a, $b )
{
if( empty( $a ) && empty( $b ) )
return [];
if( empty( $a ) )
return $b;
if( empty( $b ) )
return $a;
foreach( $b AS $i => $c ) {
$x = 0;
foreach( $a AS $ii => $d ) {
if( $c['b'] == $d['b'] ) {
$a[ $ii ]['a'] += $c['a'];
$x = 1;
break;
}
}
if( !$x )
$a[] = $b[ $i ];
}
return $a;
}
<强>输出强>
Array
(
[0] => Array
(
[a] => 11
[b] => g
)
[1] => Array
(
[a] => 13
[b] => h
)
[2] => Array
(
[a] => 3
[b] => i
)
)
答案 1 :(得分:0)
有点不同的方法
$array1 = [
[
'Contribution' => 10,
'P_Name' => 'A'
],
[
'Contribution' => 1500,
'P_Name' => 'B'
]
];
$array2 = [
[
'Contribution' => 200,
'P_Name' => 'B'
],
[
'Contribution' => 100,
'P_Name' => 'C'
],
];
$array3 = array_map(function($elem) use (&$array2){
foreach($array2 as $i => &$a2){
if($a2['P_Name'] == $elem['P_Name']){
$a2['Contribution'] += $elem['Contribution'];
return;
}
}
return $elem;
},$array1);
$array3 = array_merge(array_filter($array3),$array2);
print_r($array3);
输出:
Array
(
[0] => Array
(
[Contribution] => 10
[P_Name] => A
)
[1] => Array
(
[Contribution] => 1700
[P_Name] => B
)
[2] => Array
(
[Contribution] => 100
[P_Name] => C
)
)
答案 2 :(得分:0)
您可以使用array_reduce()
,array_map()
和array_sum()
:
<?php
function merge(array ...$sets)
{
/**
* group contributions by name
*/
$contributions = array_reduce(
$sets,
function (array $contributions, array $set) {
foreach ($set as $element) {
$name = $element['P_Name'];
$contribution = $element['Contribution'];
if (!array_key_exists($name, $contributions)) {
$contributions[$name] = [];
}
$contributions[$name][] = $contribution;
}
return $contributions;
},
[]
);
/**
* normalize the array so we remove the name as key, and return a tuple of name and contribution, with the desired
* structure
*/
return array_values(array_map(function (array $contribution, $name) {
return [
'Contribution' => array_sum($contribution),
'P_Name' => $name,
];
}, $contributions, array_keys($contributions)));
}
$a = [
[
'Contribution' => 1000,
'P_Name' => 'A',
],
[
'Contribution' => 1500,
'P_Name' => 'B',
],
];
$b = [
[
'Contribution' => 100,
'P_Name' => 'A',
],
[
'Contribution' => 200,
'P_Name' => 'B',
],
];
$merged = merge($a, $b);
var_dump($merged);
注意由于使用了可变参数,可以将任意数量的数组传递给merge()
。但需要至少PHP 5.6。
供参考,见:
有关示例,请参阅:
答案 3 :(得分:0)
输入:
$a=[['Contribution'=>1000,'P_Name'=>'A'],
['Contribution'=>1500,'P_Name'=>'B'],
['Contribution'=>2000,'P_Name'=>'C']];
$b=[['Contribution'=>100,'P_Name'=>'A'],
['Contribution'=>200,'P_Name'=>'B'],
['Contribution'=>300,'P_Name'=>'D']];
如果您使用array_column()
临时将关联键分配给子阵列,那么您可以利用array_merge_recursive()
对P_Name
值进行分组,然后调用array_sum()
进行添加给定P_Name
的值不止一个。
方法#1:(Demo)
$keyed=array_merge_recursive(array_column($a,NULL,'P_Name'),array_column($b,NULL,'P_Name'));
foreach($keyed as $p_name=>$array){
$result[]=['Contribution'=>(is_array($array['Contribution'])?array_sum($array['Contribution']):$array['Contribution']),'P_Name'=>$p_name];
}
var_export($result);
或者只是进行标准合并以创建一个数组,然后循环并添加。使用array_values()
完成输出数组以重新索引元素。
方法#2:(Demo)
foreach(array_merge($a,$b) as $array){
if(isset($result[$array['P_Name']])){
$result[$array['P_Name']]['Contribution']+=$array['Contribution'];
}else{
$result[$array['P_Name']]=$array;
}
}
$result=array_values($result);
var_export($result);
输出:(来自任何一种方法)
array (
0 =>
array (
'Contribution' => 1100,
'P_Name' => 'A',
),
1 =>
array (
'Contribution' => 1700,
'P_Name' => 'B',
),
2 =>
array (
'Contribution' => 2000,
'P_Name' => 'C',
),
3 =>
array (
'Contribution' => 300,
'P_Name' => 'D',
),
)
这不属于这个问题的范围,但最好的方法是通过数据库查询执行此分组/添加。