Question

我有10个（3用于下面的示例）集合我需要通过键合并在一起，但需要对值进行求和。我的收藏品看起来像这样：

[
    'key1' => ['value1' => 5, 'value2' => 3, 'value3' => 0],
    'key2' => ['value1' => 1, 'value2' => 6, 'value3' => 2],
    'key3' => ['value1' => 0, 'value2' => 0, 'value3' => 1],
]

[
    'key1' => ['value1' => 3, 'value2' => 1, 'value3' => 7],
    'key2' => ['value1' => 1, 'value2' => 3, 'value3' => 2],
    'key3' => ['value1' => 1, 'value2' => 6, 'value3' => 1],
]

[
    'key1' => ['value1' => 2, 'value2' => 3, 'value3' => 9],
    'key2' => ['value1' => 3, 'value2' => 8, 'value3' => 3],
    'key3' => ['value1' => 1, 'value2' => 0, 'value3' => 6],
]

我希望得到一个结果如下所示的集合：

[
    'key1' => ['value1' => 10, 'value2' => 7, 'value3' => 16],
    'key2' => ['value1' => 5, 'value2' => 17, 'value3' => 7],
    'key3' => ['value1' => 2, 'value2' => 6, 'value3' => 8],
]

我是否缺少内置的Laravel Collection方法或者实现此目的的最佳方法是什么？

编辑（更多信息）值始终为数字。任何集合中都没有字符串值。

edit2：有些人在问我尝试过什么。我试过这个有效：

$merged = [];
foreach ($seeds as $seed) {
    foreach ($seed as $location => $values) {
        foreach ($values as $key => $value) {
            $merged[$location][$key] = $value + ($merged[$location][$key] ?? 0);
        }
    }
}

我只是想知道是否有更简洁的方法来实现同样的事情，而不是使用3个foreach循环。

Answer 1

真的以为会有比循环更容易做的事情，但似乎解决方案仍然比我想出的更好。即使更改深度，Flatten也会移除键，mapToGroups仅在返回包含单个键/值对的关联数组时有效，pluck会带来一些其他困难等等。

这就是我想出来的

$test = collect([
   [
     'key1' => ['value1' => 5, 'value2' => 3, 'value3' => 0],
     'key2' => ['value1' => 1, 'value2' => 6, 'value3' => 2],
     'key3' => ['value1' => 0, 'value2' => 0, 'value3' => 1],
   ],

   [
     'key1' => ['value1' => 3, 'value2' => 1, 'value3' => 7],
     'key2' => ['value1' => 1, 'value2' => 3, 'value3' => 2],
     'key3' => ['value1' => 1, 'value2' => 6, 'value3' => 1],
   ],

   [
     'key1' => ['value1' => 2, 'value2' => 3, 'value3' => 9],
     'key2' => ['value1' => 3, 'value2' => 8, 'value3' => 3],
     'key3' => ['value1' => 1, 'value2' => 0, 'value3' => 6],
   ]
]);
$mappedCollection = collect($test->first())->keys()->mapWithKeys(function($item,$key) use($test){
   return[
      $item => $test->map(function ($mapItem, $mapKey) use($item) {         
         return $mapItem[$item];
      })
   ];
})->mapWithKeys(function($item,$key){
   $eachLine = collect($item->first())->keys()->mapWithKeys(function($mapItem) use($item){
      return[ $mapItem => $item->sum($mapItem)  ];
   });       
   return [$key =>  $eachLine];
})->all();

dd($mappedCollection);

馆藏文档来源https://laravel.com/docs/5.6/collections

Answer 2

我用laravel 7做到了这一点，以防它对某人有用

$test = collect([
   [
     'key1' => ['value1' => 5, 'value2' => 3, 'value3' => 0],
     'key2' => ['value1' => 1, 'value2' => 6, 'value3' => 2],
     'key3' => ['value1' => 0, 'value2' => 0, 'value3' => 1],
   ],

   [
     'key1' => ['value1' => 3, 'value2' => 1, 'value3' => 7],
     'key2' => ['value1' => 1, 'value2' => 3, 'value3' => 2],
     'key3' => ['value1' => 1, 'value2' => 6, 'value3' => 1],
   ],

   [
     'key1' => ['value1' => 2, 'value2' => 3, 'value3' => 9],
     'key2' => ['value1' => 3, 'value2' => 8, 'value3' => 3],
     'key3' => ['value1' => 1, 'value2' => 0, 'value3' => 6],
   ]
]);
$col = $test->reduce(function ($carry, $item) {
    return $carry->mergeRecursive($item);
}, collect([]));
$col->transform(function($item) {
    return collect($item)->map(function ($item2) {
        return collect($item2)->sum();
    });
});

合并两个Laravel集合并求和值

2 个答案: