Question

我得到了一个调查表的设置，每个调查都有一些与自身相关的答案（一对多）。我想进行一个查询来计算每个surveyId的答案数，分别为parameter1 = 0和parameter1 = 1。

我试着这样做：

$surveysWithRepliesExposed = Survey::where('title', 'LIKE', "%$name%")
    ->with(array('surveyAnswerSets' => function($query){
        $query->where('parameter1', 0)
        ->selectRaw('surveyId, count(*) as repliesExposed')
        ->groupBy('surveyId');
    }))
    ->select($columns);

$surveysWithRepliesExposed = Survey::where('title', 'LIKE', "%$name%")
    ->with(array('surveyAnswerSets' => function($query){
        $query->where('parameter1', 1)
        ->selectRaw('surveyId, count(*) as repliesControl')
        ->groupBy('surveyId');
    }))
    ->select($columns);

但是现在我得到两个看起来几乎相同的集合：

{
    "surveyId": 11,
    "title": "A survey",
    "startDate": "2015-04-16",
    "endDate": "2015-04-30",
    "survey_answer_sets": [
        {
            "surveyId": 11,
            "repliesExposed": 212
        }
    ]
}

另一个

{
    "surveyId": 11,
    "title": "A survey",
    "startDate": "2015-04-16",
    "endDate": "2015-04-30",
    "survey_answer_sets": [
        {
            "surveyId": 11,
            "repliesControl": 56
        }
    ]
}

我如何合并这些以便

{
    "surveyId": 11,
    "title": "A survey",
    "startDate": "2015-04-16",
    "endDate": "2015-04-30",
    "survey_answer_sets": [
        {
            "surveyId": 11,
            "repliesExposed": 212
            "repliesControl": 56
        }
    ]
}

Answer 1

我在朋友的帮助下解决了这个问题。

这段代码符合我的要求！

$surveys = Survey::leftJoin('SurveyAnswerSets', 'Surveys.surveyId', '=', 'SurveyAnswerSets.surveyId')
    ->select(
        DB::raw(
            "Surveys.surveyId,
           Surveys.title,
           Surveys.startDate,
           Surveys.endDate,
           sum(case when SurveyAnswerSets.isRefGroup = 0 then 1 else 0 end) repliesExposed,
           sum(case when SurveyAnswerSets.isRefGroup = 1 then 1 else 0 end) repliesControl,
           sum(1) repliesTotal"
        )
    )
    ->where('SurveyAnswerSets.isComplete', 1)
    ->where('Surveys.title', 'LIKE', "%$name%")
    ->where('Surveys.isTemplate', 0)
    ->groupBy('Surveys.surveyId')->get();

合并两个Eloquent系列

1 个答案: