Question

您好我打了一堵砖墙，我一直在为我的应用重新设计菜单导航。我设法做到了。但现在我的应用程序的一个功能已决定停止运行。

这个想法是你摇动你的手机并随机选择一张图片，与应用程序分开的代码工作得很好，正如它在以前版本的所有版本上所做的那样，我甚至快速运行它的现有形式就可以了拥有以防万一，它完美无缺。

希望有人可以指出我出错的方向。

我的代码如下;

    import Foundation
import UIKit


class cocktailChoice: UIViewController {

    @IBOutlet weak var drinkImage: UIImageView!

    var drinkNamesArray:[String] = ["cocktailList0","cocktailList1","cocktailList2","cocktailList3","cocktailList4","cocktailList5","cocktailList6","cocktailList7","cocktailList8","cocktailList9","cocktailList10","cocktailList11","cocktailList12","cocktailList13","cocktailList14","cocktailList15","cocktailList16","cocktailList17","cocktailList18","cocktailList19","cocktailList20","cocktailList21","cocktailList22","cocktailList23","cocktailList24","cocktailList25","cocktailList26","cocktailList27","cocktailList28","cocktailList29","cocktailList30","cocktailList31"]

    override func viewDidLoad() {
        self.view.addGestureRecognizer(self.revealViewController().panGestureRecognizer())
    }

    override func motionEnded(_ motion: UIEventSubtype, with event: UIEvent?) {

        if motion == .motionShake{

            let firstRandomNumber = Int(arc4random_uniform(32))

            let DrinkString:String = self.drinkNamesArray[firstRandomNumber]

            self.drinkImage.image = UIImage(named: DrinkString)

        }

    }

}

它编译没有错误，IBOutlet是连接，它没有我能看到的错误，但摇动动作不想播放。现在变得非常沮丧。

Answer 1

您可以尝试使用此代码来代替此部分if motion == .motionShake{：

if(event.subtype == .motionShake) {
        print("Shake event!")
    }

动作摇动动作不再适用于快速

1 个答案: