超级Android PlayBack&同时录制

时间:2017-08-18 20:46:17

标签: android c++ audio audio-recording superpowered

我正在使用Superpowered Android C ++库开发调音台,我在播放时遇到播放器问题,播放器没有播放,只有录音机正在录音。下面是代码,任何人都可以指导我在哪里放错了东西

bool processRecording(short int *input, unsigned int numberOfSamples) {
pthread_mutex_lock(&mutex);
if (askRecording) {
    unsigned int data = 0;

       SuperpoweredShortIntToFloat(input, stereoBufferRecording, numberOfSamples);
       data = recorder->process(stereoBufferRecording, NULL, numberOfSamples);

       playerA->process( musicBuffer, false, numberOfSamples, 0.5f );
       SuperpoweredShortIntToFloat(input, stereoBufferRecording, numberOfSamples);

       SuperpoweredFloatToShortInt(musicBuffer, input, numberOfSamples);

       pthread_mutex_unlock(&mutex);
       return true;
       }
pthread_mutex_unlock(&mutex);
return false;
}

有没有人有想法让它在正确的地方?

@Gabor建议的更改之后是代码段

bool processRecording(short int *input, unsigned int numberOfSamples) {

pthread_mutex_lock(&mutex);
if (askRecording) {
    unsigned int data = 0;
    SuperpoweredShortIntToFloat(input, stereoBufferRecording, numberOfSamples);

    playerA->process( musicBuffer, false, numberOfSamples, 1.0f );

//=====================================================================================
 // ================== Mixing Two Buffer ==================

    mixerInputs[0] = musicBuffer;
    mixerInputs[1] = stereoBufferRecording;
    mixerInputs[2] = NULL;
    mixerInputs[3] = NULL;

    mixerOutputs[0] = outputBuffer;
    mixerOutputs[1] = NULL;

    float inputLevels[] = { 0.5f, 0.5f, 1.0f, 1.0f, 1.0f, 1.0f, 1.0f, 1.0f };
    float outputLevels[] = { 1.0f, 1.0f };
    __android_log_print(ANDROID_LOG_INFO, "NativeSuperpoweredRecorder  ", " processRecording 2>>");
    mixerBackend->process(mixerInputs, mixerOutputs, inputLevels, outputLevels, NULL, NULL, numberOfSamples);

//=====================================================================================

    data = recorder->process(mixerOutputs[0], NULL, numberOfSamples);
    SuperpoweredFloatToShortInt(musicBuffer, input, numberOfSamples);
    pthread_mutex_unlock(&mutex);
    return true;
}
pthread_mutex_unlock(&mutex);

return false; }

1 个答案:

答案 0 :(得分:4)

这是您在代码中执行的操作:

输入 - > stereoBufferRecording->记录器

输入 - > stereoBufferRecording->

播放器 - > musicBuffer->输入

当askRecording为false时,玩家根本不玩。

我猜测“输入”是同样的缓冲区,也是“输出”?