Question

我有一个带有文本属性的Label绑定到类：

 <TextBlock Visibility="Hidden" TextTrimming="WordEllipsis" Grid.Row="0" Grid.Column="0" VerticalAlignment="Center" Text="{Binding DisplayText}" TextWrapping="Wrap" FontSize="10"></TextBlock>

如果DisplayText是链接，则应使用超链接。我绑定的类也提供Uri和布尔isLink。我尝试将Hyperlink元素放在Textblock内，并将其NavigateUri设置为类中的Uri，但这对我不起作用。有人为此提供了一个干净的解决方案吗？

Answer 1

我认为您可以根据属性绑定模板。

 <ContentControl>
                <ContentControl.Style>
                    <Style TargetType="ContentControl">
                        <Style.Triggers>
                            <DataTrigger Binding="{Binding IsLink}" Value="True">
                                <Setter Property="ContentTemplate"  >
                                    <Setter.Value>
                                        <DataTemplate>
                                            <TextBlock>
                                                 <Hyperlink  NavigateUri="{Binding DataContext.Url, RelativeSource={RelativeSource Mode=FindAncestor,      
                        AncestorType= ContentControl} }">
                                                    <TextBlock Text="{Binding DataContext.DisplayText, RelativeSource={RelativeSource Mode=FindAncestor,      
                        AncestorType=ContentControl} }"/>
                                                </Hyperlink>
                                            </TextBlock>
                                        </DataTemplate>
                                    </Setter.Value>
                                </Setter>
                            </DataTrigger>
                            <DataTrigger Binding="{Binding IsLink}" Value="False">
                                <Setter Property="ContentTemplate" >
                                    <Setter.Value>
                                        <DataTemplate>
                                            <TextBlock Text="{Binding DataContext.DisplayText,RelativeSource={RelativeSource Mode=FindAncestor,      
                        AncestorType=ContentControl} }"/>
                                        </DataTemplate>
                                    </Setter.Value>
                                </Setter>
                            </DataTrigger>
                        </Style.Triggers>
                    </Style>
                </ContentControl.Style>
            </ContentControl>

Answer 2

您可以使用这两个控件，并根据isLink属性更改其可见性。

<Grid>
    <TextBlock>
        <Hyperlink NavigateUri="{Binding Uri}"
                   RequestNavigate="Hyperlink_RequestNavigate">
            <TextBlock Text="{Binding DisplayText}"/>
        </Hyperlink>
        <TextBlock.Style>
            <Style TargetType="TextBlock">
                <Setter Property="Visibility" Value="Visible"/>
                <Style.Triggers>
                    <DataTrigger Binding="{Binding IsLink}" Value="False">
                        <Setter Property="Visibility" Value="Collapsed"/>
                    </DataTrigger>
                </Style.Triggers>
            </Style>
        </TextBlock.Style>
    </TextBlock>
    <TextBlock Text="{Binding DisplayText}">
        <TextBlock.Style>
            <Style TargetType="TextBlock">
                <Setter Property="Visibility" Value="Visible"/>
                <Style.Triggers>
                    <DataTrigger Binding="{Binding IsLink}" Value="True">
                        <Setter Property="Visibility" Value="Collapsed"/>
                    </DataTrigger>
                </Style.Triggers>
            </Style>
        </TextBlock.Style>
    </TextBlock>
</Grid>

在代码背后：

private void Hyperlink_RequestNavigate(object sender, RequestNavigateEventArgs e)
{
    System.Diagnostics.Process.Start(new System.Diagnostics.ProcessStartInfo(e.Uri.AbsoluteUri));
    e.Handled = true;
}

文本块有条件地作为链接

2 个答案: