使用Python

Question

我想对数据框df的三列进行计算。为了做到这一点，我想在三列表中运行资产（加密货币）列表的价格，以便在有足够数据后计算它们的指数移动平均值。

def calculateAllEMA(self,values_array):
    df = pd.DataFrame(values_array, columns=['BTC', 'ETH', 'DASH'])
    column_by_search = ["BTC", "ETH", "DASH"]
    print(df)
    for i,column in enumerate(column_by_search):
        ema=[]
        # over and over for each day that follows day 23 to get the full range of EMA
        for j in range(0, len(column)-24):
            # Add the closing prices for the first 22 days together and divide them by 22.
            EMA_yesterday = column.iloc[1+j:22+j].mean()
            k = float(2)/(22+1)
            # getting the first EMA day by taking the following day’s (day 23) closing price multiplied by k, then multiply the previous day’s moving average by (1-k) and add the two.
            ema.append(column.iloc[23 + j]*k+EMA_yesterday*(1-k))
        print("ema")
        print(ema)
        mean_exp[i] = ema[-1]
    return mean_exp

然而，当我打印len(column)-24中的内容时，我得到了-21（-24 + 3？）。因此，我无法完成循环。我如何应对此错误以获得资产的指数移动平均值？

我尝试将this link from iexplain.com应用于指数移动平均线的伪代码。

如果你有任何更容易的想法，我愿意听。

以下是我在用于计算错误时使用的数据：

        BTC     ETH    DASH
0   4044.59  294.40  196.97
1   4045.25  294.31  196.97
2   4044.59  294.40  196.97
3   4045.25  294.31  196.97
4   4044.59  294.40  196.97
5   4045.25  294.31  196.97
6   4044.59  294.40  196.97
7   4045.25  294.31  196.97
8   4045.25  294.31  196.97
9   4044.59  294.40  196.97
10  4045.25  294.31  196.97
11  4044.59  294.40  196.97
12  4045.25  294.31  196.97
13  4045.25  294.32  197.07
14  4045.25  294.31  196.97
15  4045.41  294.46  197.07
16  4045.25  294.41  197.07
17  4045.41  294.41  197.07
18  4045.41  294.47  197.07
19  4045.25  294.41  197.07
20  4045.25  294.32  197.07
21  4045.43  294.35  197.07
22  4045.41  294.46  197.07
23  4045.25  294.41  197.07

Answer 1

原始答案中的

pandas.stats.moments.ewma已被弃用。

相反，您可以使用pandas.DataFrame.ewm作为记录here。

下面是一个包含随机数据的完整代码段，可以使用指定列的计算ewma构建数据框。

<强>代码：

# imports
import pandas as pd
import numpy as np

np.random.seed(123)

rows = 50
df = pd.DataFrame(np.random.randint(90,110,size=(rows, 3)), columns=['BTC', 'ETH', 'DASH'])
datelist = pd.date_range(pd.datetime(2017, 1, 1).strftime('%Y-%m-%d'), periods=rows).tolist()
df['dates'] = datelist 
df = df.set_index(['dates'])
df.index = pd.to_datetime(df.index)

def ewmas(df, win, keepSource):
    """Add exponentially weighted moving averages for all columns in a dataframe.

    Arguments: 
    df -- pandas dataframe
    win -- length of ewma estimation window
    keepSource -- True or False for keep or drop source data in output dataframe

    """

    df_temp = df.copy()

    # Manage existing column names
    colNames = list(df_temp.columns.values).copy()
    removeNames = colNames.copy()

    i = 0
    for col in colNames:

        # Make new names for ewmas
        ewmaName = colNames[i] + '_ewma_' + str(win)   

        # Add ewmas
        #df_temp[ewmaName] = pd.stats.moments.ewma(df[colNames[i]], span = win)
        df_temp[ewmaName] = df[colNames[i]].ewm(span = win, adjust=True).mean()

        i = i + 1

    # Remove estimates with insufficient window length
    df_temp = df_temp.iloc[win:]

    # Remove or keep source data
    if keepSource == False:
        df_temp = df_temp.drop(removeNames,1)

    return df_temp

# Test run
df_new = ewmas(df = df, win = 22, keepSource = True)
print(df_new.tail())

<强>输出：

             BTC  ETH   DASH  BTC_ewma_22  ETH_ewma_22    DASH_ewma_22
dates                                                             
2017-02-15   91   96    98    98.752431    100.081052     97.926787
2017-02-16  100  102   102    98.862445    100.250270     98.285973
2017-02-17  100  107    97    98.962634    100.844749     98.172712
2017-02-18  103  102    91    99.317826    100.946384     97.541684
2017-02-19   99  104    91    99.289894    101.214755     96.966758

使用df_new[['BTC', 'BTC_ewma_22']].plot()绘制：

Answer 2

在循环for i,column in enumerate(column_by_search):中，您遍历column_by_search列表中的元素，即列依次取值“BTC”，“ETH”，“DASH”。因此，len(column)将为您提供字符串“BTC”的长度，实际上为3。

请尝试df[column]，这将返回包含所需列中元素的列表，您可以迭代它。