我无法弄清楚如何让tf.train.ExponentialMovingAverage
工作。以下是在简单的w
等式中查找y_ = x * w
的简单代码。 m
是移动平均线。为什么None
的代码返回m
?如何让它返回移动平均值?
import numpy as np
import tensorflow as tf
w = tf.Variable(0, dtype=tf.float32)
ema = tf.train.ExponentialMovingAverage(decay=0.9)
m = ema.apply([w])
x = tf.placeholder(tf.float32, [None])
y = tf.placeholder(tf.float32, [None])
y_ = tf.multiply(x, w)
with tf.control_dependencies([m]):
loss = tf.reduce_sum(tf.square(tf.subtract(y, y_)))
optimizer = tf.train.GradientDescentOptimizer(learning_rate=0.001)
train = optimizer.minimize(loss)
with tf.Session() as sess:
sess.run(tf.global_variables_initializer())
for i in range(20):
_, w_, m_ = sess.run([train, w, m], feed_dict={x: [1], y: [10]})
print(w_, ',', m_)
输出结果为:
0.02 , None
0.03996 , None
0.0598801 , None
0.0797603 , None
0.0996008 , None
0.119402 , None
0.139163 , None
0.158884 , None
0.178567 , None
0.19821 , None
0.217813 , None
0.237378 , None
0.256903 , None
0.276389 , None
0.295836 , None
0.315244 , None
0.334614 , None
0.353945 , None
0.373237 , None
0.39249 , None
答案 0 :(得分:7)
这是因为m
(python)变量不包含操作的结果而是操作本身。请参阅doc:
Returns: An Operation that updates the moving averages.
要访问平均值,您需要在图表中创建一个新元素:
av = ema.average(w)
然后:
_, w_, av_ = sess.run([train, w, av], feed_dict={x: [1], y: [10]})
print(w_, ',', av_)
将打印
[0.020000001, 0.0]
[0.039960001, 0.0020000006]
[0.059880082, 0.0057960013]
[0.07976032, 0.01120441]
[0.099600799, 0.018060002]
import tensorflow as tf
w = tf.Variable(0, dtype=tf.float32)
ema = tf.train.ExponentialMovingAverage(decay=0.9)
m = ema.apply([w])
av = ema.average(w)
x = tf.placeholder(tf.float32, [None])
y = tf.placeholder(tf.float32, [None])
y_ = tf.multiply(x, w)
with tf.control_dependencies([m]):
loss = tf.reduce_sum(tf.square(tf.subtract(y, y_)))
optimizer = tf.train.GradientDescentOptimizer(learning_rate=0.001)
train = optimizer.minimize(loss)
with tf.Session() as sess:
sess.run(tf.global_variables_initializer())
for i in range(20):
_, w_, av_ = sess.run([train, w, av], feed_dict={x: [1], y: [10]})
print(w_, ',', av_)