取消组合查询结果

Question

如果两个请求都返回相同的数据，那么它们将被＆＃34;分组＆＃34;进入工会。

query1 return X 
query2 return X

query1 union query2 renurn only X

But i need to get
+---+
| X |
| X |
+---+

如果每个请求返回不相等的数据，则union的结果将为consist of two lines. This is normal。

mysql> select count(pid) from posts 
where uid_posts=8890 and postacc=1 and postcomacc=1 
union
select count(comid) from coms join posts on pid_coms=pid 
where uid_posts!=8890 and uid_coms=8890 and postacc=1 and postcomacc=1;
+------------+
| count(pid) |
+------------+
|          1 |
|          2 |
+------------+

I want to achieve this。

但是联合的常见查询＆＃34;分组＆＃34;这些相同的价值观。

mysql> select count(pid) from posts
where uid_posts=8890 and postacc=1 and postcomacc=1 ;
+------------+
| count(pid) |
+------------+
|          2 |
+------------+


mysql>  select count(comid) from coms join posts on pid_coms=pid 
where uid_posts!=8890 and uid_coms=8890 and postacc=1 and postcomacc=1;
+--------------+
| count(comid) |
+--------------+
|            2 |
+--------------+



//thay are "grouped" :( below

mysql> select count(pid) from posts
where uid_posts=8890 and postacc=1 and postcomacc=1 
union
select count(comid) from coms join posts on pid_coms=pid 
where uid_posts!=8890 and uid_coms=8890 and postacc=1 and postcomacc=1;
+------------+
| count(pid) |
+------------+
|          2 |
+------------+

如何取消组合这些结果？

或者我是否需要重新编写整个查询？

STOP！ UNION ALL必须帮我。

Answer 1

使用union all：

select count(pid)
from posts 
where uid_posts = 8890 and postacc = 1 and postcomacc = 1 
union all
select count(comid)
from coms join
     posts
     on pid_coms = pid 
where uid_posts <> 8890 and uid_coms = 8890 and postacc = 1 and postcomacc = 1

我还会添加第二列来指定哪个计数与哪个查询相关。