Question

我想创建一个迭代器，我可以将其传递给方法来调用。

#!/usr/bin/env ruby

puts "------------------------------------"
puts "1 This works."
puts "------------------------------------"       
1.times {|who| puts "Position #{who} works!"}

puts "------------------------------------"
puts "2 This works."
puts "------------------------------------"       
aBlock = Proc.new { |who| puts "Position #{who} also works!" }       
2.times &aBlock

puts "------------------------------------"
puts "3 This works."
puts "------------------------------------"       
def eachIndex
  3.times { |i| yield i }
end

eachIndex &aBlock

puts "------------------------------------"
puts "4 This does not work."
puts "------------------------------------"       
iterator = lambda { |name| yield name }       
iterator.call(4) {|who| puts "Does not work #{who}:-("}

puts "------------------------------------"
puts "5 This does not work."
puts "------------------------------------"       
iterator = lambda { |name,&block| yield name }       
iterator.call(5) {|who| puts "Does not work #{who}:-("}

puts "------------------------------------"
puts "6 This does not work."
puts "------------------------------------"       
iterator = Proc.new { |name,&block| yield name }       
iterator.call(6) {|who| puts "Does not work #{who}:-(" }

lambda或proc是Ruby中的迭代器吗？我想将它们作为参数传递给一个类。

Answer 1

以下是这样做的方法

iterator = -> (name, &block) { block.call name }
iterator.call(4) { |who| puts "It works now #{who} :)" }

P.S。注意我在这里使用lambda的快捷方式，->称为stabby lambda

在Ruby中，你可以使用lambda或proc调用方法来调用迭代器吗？

1 个答案: