如何从特征矩阵映射/构建c ++向量？

Question

MatrixXf A = MatrixXf::Random(3, 3);

MatrixXf B = A.row(1);

std::vector<float> vec;

我想建立矢量＆＃34; vec＆＃34;使用行特征矩阵＆＃34; B＆＃34;中的元素。像这样的东西＆＃34; vec = B.data（）＆＃34;

Answer 1

除了明显的答案（手动kubectl edit deployment nginx-deployment或预分配+索引索引分配），您可以使用apiVersion: apps/v1beta1 kind: Deployment metadata: name: nginx-deployment spec: replicas: 2 # tells deployment to run 2 pods matching the template template: # create pods using pod definition in this template metadata: # unlike pod-nginx.yaml, the name is not included in the meta data as a unique name is # generated from the deployment name labels: app: nginx spec: containers: - name: nginx image: nginx:1.7.9 ports: - containerPort: 80 返回的基指针直接初始化它：

push_back

请注意，Eigen可能会使用内存对齐来利用SSE系列指令，因此它可能无法在更高维度下正常工作。

Answer 2

只需使用循环：

MatrixXf A = MatrixXf::Random(3, 3);
MatrixXf B = A.row(1);
std::vector<float> vec(B.size());
for(size_t row=0; row < vec.size(); row++) {
    vec[row] = B[row];
}