我试图为我的列表视图项实现滑动,我有隐藏元素(如按钮) 我想要向左/向右滑动项目以显示此按钮。一切都很完美。除了我不能正常点击项目或按钮。因为事件MotionEvent.ACTION_UP总是被触发。 当我只是简单点击/触摸项目
时记录 Action DOWN
OLD X = -329.0
DX = -329.0
MOVE RIGHT
OLD X = -329.0
DX = -330.5
MOVE RIGHT
OLD X = -329.0
DX = -330.95996
MOVE RIGHT
Action UP
能帮到我吗? 点击试图使用此代码的项目
float cx = event.getX();
if(cx<width && cx>(width-150)) {
和我的代码
swipeLayout.setOnTouchListener(new View.OnTouchListener() {
private boolean canClick = false;
@Override
public boolean onTouch(View view, MotionEvent event) {
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
x1 = event.getX();
dX = view.getX() - event.getRawX();
dY = view.getY() - event.getRawY();
Logger.e("Action DOWN");
oldX = dX;
return true;
case MotionEvent.ACTION_MOVE:
Logger.e("OLD X = " + oldX);
Logger.e("DX = " + dX);
dX = view.getX() - event.getRawX();
if (oldX < dX) {
Logger.e("MOVE LEFT");
view.animate().x(-100).setDuration(50).start();
break;
}
if (oldX > dX) {
Logger.e("MOVE RIGHT");
view.animate().x(0).setDuration(50).start();
break;
}
case MotionEvent.ACTION_UP:
Logger.e("Action UP");
}
return false;
}
});
答案 0 :(得分:0)
考虑使用GestureDetector
来处理滑动。
以下是可能的示例:
new GestureDetector(context, new GestureDetector.SimpleOnGestureListener(){
@Override
public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX,
float velocityY) {
// Here you handle short quick swipe gesture
return super.onFling(e1, e2, velocityX, velocityY);
}
@Override
public boolean onScroll(MotionEvent e1, MotionEvent e2, float distanceX,
float distanceY) {
// Here you handle slow finger movement across the screen
return super.onScroll(e1, e2, distanceX, distanceY);
}
});