在我的程序中,我在手指向下和移动时绘制一个矩形而不是在手指向上后擦除它。这是为了向用户显示他/她用作“猜测”以找到根的值的范围。但矩形永远不会出现!但是,如果我删除调用以关闭“action_up”部分中的矩形,则用户可以绘制矩形。 这是代码:
在绘图功能中:
if(dataline>1)//if greater than 1, draw rectangle
{
myPaint.setColor(Color.CYAN);
canvas.drawRect(tX1,0, tX2,canvas.getHeight(),myPaint);
}
运动事件功能中的: public boolean onTouchEvent(MotionEvent ev){ final int action = ev.getAction();
switch (action) {
case MotionEvent.ACTION_DOWN: {
final float x = ev.getX();
final float y = ev.getY();
// Remember where we started
mLastTouchX = x;
mLastTouchY = y;
tX1=(int)ev.getX();
tX2=tX1;
x_1 = ev.getX();
x_1=(x_1-X1)/(zoom_x);
clicks= 1;
tX1=(int) ev.getX();//set first x coord
tX2=tX1;// make second x coord equal to the first
}
case MotionEvent.ACTION_MOVE: {
final float x = ev.getX();
final float y = ev.getY();
// Calculate the distance moved
final float dx = x - mLastTouchX;
final float dy = y - mLastTouchY;
mLastTouchX = x;
mLastTouchY = y;
dataline=2;//let onDraw() draw the rectangle while dragging finger
tX2+= (int)dx;// find new second coordinate
}
case MotionEvent.ACTION_UP: {
dataline=0;//if commented out, rectangle is drawn otherwise, it is never seen.
}
}
return true;
}
答案 0 :(得分:1)
问题解决了!我已经知道你必须在每种情况下都给出一个return语句,否则它只会运行所有的情况。