Question

下面是我绘制黄色房子的海龟计划。我无法找到一种方法来创建一个for循环，以保持龟程序的简短。有没有人知道如何为下面的程序创建一个循环？

import turtle
import math
def yellowHouse () :
  wn=turtle.Screen()
  wn.title("Yellow House")
  wn.bgcolor("Blue")
  #sideLength = 200
  house=turtle.Turtle()
  Diagonal_length= 0.5*math.sqrt(2 *(200 ** 2 ))
  house.pensize(5)
  house.speed(4.6)
  house.color("Yellow")
  house.left(90)
  house.forward(200)
  house.right (135)
  house.forward(Diagonal_length)
  house.right(90)
  house.forward(Diagonal_length)
  house.left(135)
  house.forward(200)
  house.left(135)
  house.forward(Diagonal_length)
  house.right(90)
  house.forward(Diagonal_length)
  house.left(135)
  house.forward(200)
  house.right(135)
  house.forward(Diagonal_length)
  house.right(90)
  house.forward(Diagonal_length)
  house.right(45)
  house.forward(200)
  house.left(90)
  wn.mainloop()
yellowHouse ()

Answer 1

由于您正在重建一个形状的房子，我会选择标记而不是绘图：

from turtle import Turtle, Screen

def yellowHouse(side_length):
    wn.register_shape("brick", ((0, 0), (-0.5, -0.5), (0.5, -0.5)))
    house = Turtle('brick', visible=False)
    house.shapesize(stretch_wid=side_length, outline=5)
    house.color("yellow", wn.bgcolor())
    house.penup()

    for angle in range(360, 0, -90):
        house.setheading(angle)
        house.stamp()

    house.forward(side_length)
    house.stamp()

wn = Screen()
wn.title("Yellow House")
wn.bgcolor("blue")

yellowHouse(200)

wn.exitonclick()

此解决方案将房子打印在屏幕中央。你传递你想要的房子的大小。（而且它的代码少了1/3。）

Answer 2

创建循环是使程序代码简短的好方法，您可以通过多种方式实现这一点，在您的示例中：

方法1

使用循环绘制正方形，然后绘制对角线交叉线和顶部

import turtle
def yellowHouse() :
  wn=turtle.Screen()
  wn.title("Yellow House")
  wn.bgcolor("Blue")
  house=turtle.Turtle()
  house.pensize(5)
  house.speed(4.6)
  house.color("Yellow")
  side = 200
  diag = (2*(side**2))**0.5
  ang = 90
  for i in range(4):
    house.fd(side)
    house.lt(ang)
  house.lt(ang/2)
  moves = [(diag,ang),(diag/2,ang),(diag/2,ang),(diag,ang)]
  for (move,turn) in moves:
    house.fd(move)
    house.lt(turn)
  wn.mainloop()

yellowHouse()

方法2

使用循环遍历步骤来绘制整个形状

import turtle
def yellowHouse() :
  wn=turtle.Screen()
  wn.title("Yellow House")
  wn.bgcolor("Blue")
  house=turtle.Turtle()
  house.pensize(5)
  house.speed(4.6)
  house.color("Yellow")
  side = 200
  diag = (2*(side**2))**0.5
  ang = 90
  moves = [(side,ang),(side,ang),(side,ang),(side,ang),
          (0,ang/2),(diag,ang),(diag/2,ang),(diag/2,ang),(diag,ang)]
  for (move,turn) in moves:
    house.fd(move)
    house.lt(turn)
  wn.mainloop()

yellowHouse()

注意我们不需要导入数学，因为我们只需要sqrt()来计算我们可以使用**指数运算符sqrt(x)实现的平方根。 x**0.5

Answer 3

这是你的forloop代码，你必须只维护事件和事件值索引..

import turtle
import math
def yellowHouse() :
  wn=turtle.Screen()
  wn.title("Yellow House")
  wn.bgcolor("Blue")
  #sideLength = 200
  house=turtle.Turtle()
  Diagonal_length= 0.5*math.sqrt(2 *(200 ** 2 ))
  event = ["pensize","speed","color","left","forward","right","forward","right","forward","left","forward","left","forward","right","forward","left","forward","right","forward","right","forward","right","forward","left"]
  event_val = [5,4.6,"Yellow",90,200,135,Diagonal_length,90,Diagonal_length,135,200,135,Diagonal_length,90,Diagonal_length,135,200,135,Diagonal_length,90,Diagonal_length,45,200,90]
  event_zip = zip(event, event_val)
  for i,j in event_zip:
    if type(j).__name__ == "str":
        eval("house.{}('{}')".format(i,j))
    else:
        eval("house.{}({})".format(i,j))
yellowHouse()

缩短一个房子的Python龟程序

3 个答案: