Question

我正在尝试完成一个课程，我做得很好。这是一个简单的python龟图形游戏，你试图避免毒点并导航到正方形。但是，在用户点击屏幕之前，我的程序会立即启动。我怎样才能解决这个问题？谢谢！

我的代码：

# This game involves avoiding red poison blobs while attempting to navigate to
# a square. If you hit the blob, you begin to speed up, making it more difficult
# not to hit more. Additionally, you lose a point. If you reach the square you
# get a point.

import turtle
import math
import random

# screen
wn = turtle.Screen()
wn.bgcolor("black")
wn.tracer(3)

# Draw border
pen1 = turtle.Turtle()
pen1.color("white")
pen1.penup()
pen1.setposition(-275,-275)
pen1.pendown()
pen1.pensize(5)
for side in range(4):
    pen1.forward(550)
    pen1.left(90)
pen1.hideturtle()

# player
player = turtle.Turtle()
player.color("dark green")
player.shape("turtle")
player.penup()

# poisonBlob
maxpoisonBlob = 15
poisonBlob = []

for a in range(maxpoisonBlob):
    poisonBlob.append(turtle.Turtle())
    poisonBlob[a].color("dark red")
    poisonBlob[a].shape("circle")
    poisonBlob[a].shapesize(4, 4, 4)
    poisonBlob[a].penup()
    poisonBlob[a].speed(0)
    poisonBlob[a].setposition(random.randint(-255, 255), random.randint(-255, 255))

maxfood = 1
food = []

for a in range(maxfood):
        food.append(turtle.Turtle())
        food[a].color("light blue")
        food[a].shape("square")
        food[a].penup()
        food[a].speed(0)
        food[a].setposition(random.randint(-240, 240), random.randint(-240, 240))

# speed variable
speed = 6.5

def turnleft():
    player.left(30)

def turnright():
    player.right(30)

def increasespeed():
    global speed
    speed += 1

def touchPoison(t1, t2):
    d = math.sqrt(math.pow(t1.xcor()-t2.xcor(),2) + math.pow(t1.ycor()-t2.ycor(),2))
    if d < 50:
        return True
    else:
        return False

def touchfood(z1, z2):
        d = math.sqrt(math.pow(z1.xcor()-z2.xcor(),2) + math.pow(z1.ycor()-z2.ycor(),2))
        if d < 20:
                return True
        else:
                return False


turtle.listen()
turtle.onkey(turnleft, "Left")
turtle.onkey(turnright, "Right")


def main():
    print("Help your turtle navigate red poison blobs while attempting to navigate to the\n"
          "food! If you hit the poison, you begin to speed up, making it more difficult\n"
          "not to hit more. Additionally, you lose a point. If you reach the square you\n"
          "get a point. To navigate, click the screen, and then use the right and left\n"
          "arrow keys. Quickly, your turtle is running away!")

    score = 0

    while True:
        player.forward(speed)

        # turtle boundary
        if player.xcor() > 260 or player.xcor() < -260:
            player.right(180)

        # turtle boundary
        if player.ycor() > 260 or player.ycor() < -260:
            player.right(180)

        # move poison
        for a in range(maxpoisonBlob):
            poisonBlob[a].forward(3)

           # Poison boundaries
            if poisonBlob[a].xcor() > 220 or poisonBlob[a].xcor() < -220:
                poisonBlob[a].right(180)

            # Poision boundaries
            if poisonBlob[a].ycor() > 220 or poisonBlob[a].ycor() < -220:
                poisonBlob[a].right(180)     

            # Poison touching
            if touchPoison(player, poisonBlob[a]):
                increasespeed()
                poisonBlob[a].setposition(random.randint(-230, 230), random.randint(-230, 230))
                poisonBlob[a].right(random.randint(0,360))
                score -= 1
                #Draw score
                pen1.undo()
                pen1.penup()
                pen1.hideturtle()
                pen1.setposition(-260, 280)
                scorestring = "Score: %s" %score
                pen1.write(scorestring, font=("Calibri", 12))

        for a in range(maxfood):

            #Positive Point Checking
            if touchfood(player, food[a]):
                food[a].setposition(random.randint(-230, 230), random.randint(-230, 230))
                score += 1
                #Draw Score
                pen1.undo()
                pen1.penup()
                pen1.hideturtle()
                pen1.setposition(-260, 280)
                scorestring = "Score: %s" %score
                pen1.write(scorestring, font=("Calibri", 12))

if __name__ == "__main__":
    main()

Answer 1

一般来说，我们尽量不直接回答作业问题，但我会给你一些指导。

我不熟悉您正在使用的库，但基本的想法是您需要等到用户点击屏幕才能继续使用。我的理解是你想在main中的print（）函数之后这样做，这样用户就必须阅读消息，然后点击继续。

快速搜索显示此链接：Turtle in python- Trying to get the turtle to move to the mouse click position and print its coordinates

这详细介绍了onscreenclick（）事件。通过你的onkey（）方法来判断你已经熟悉了对事件的绑定，所以你应该能够利用这些知识绑定到onscreenclick（）事件，然后你只需要稍微破解你的代码就可以了。 39;执行游戏直到onscreenclick（）事件发生。

如果这还不够清楚，请帮助我了解您的困惑在哪里，我会进一步提供帮助。谢谢！

Answer 2

您可以先定义一个函数，在其中调用“if”语句，然后通过在其中插入新定义的函数来使用<dependency> <groupId>com.sun</groupId> <artifactId>tools</artifactId> <version>${java.version}</version> <scope>system</scope> <systemPath>${java.home}/../lib/tools.jar</systemPath> </dependency>，如下所示：

turtle.onscreenclick()

请务必在最后插入所有内容！

现在，在函数定义中的函数名后面的括号中添加（x，y），将用户在图形窗口中点击的点分配给相应的（x，y）坐标，从而激活函数到期点击屏幕的动作。我成功地做到了这一点，所以我可以向你保证它有效！我希望这有帮助！：）

如何让这个程序在开始之前等待屏幕点击？

2 个答案: