Question

我正在尝试通过编码高斯对数似然来学习R来解决optim()，但经过几个小时的汗水后，我仍然没有做到。（这是自学，不是作业。）

我在许多用户编写的函数中遵循约定，该函数编写类似loglik <- function(theta, y, x)的函数，其中theta是权重beta和方差sigma，{{的向量1}}是结果，y是数据。

我的完整代码包含模拟数据如下。运行它，你会发现与x相比，我的功能远远不够。任何人都可以告诉我哪里出错了？

lm()

这是输出：

# random data
set.seed(111)
y = sample(1:100,100)
x1 = sample(1:100,100)*rnorm(1,0)
x2 = sample(x1)*rnorm(1,0)
x3 = sample(x2)*rnorm(1,0)
dat = data.frame(x1,x2,x3)

# define gaussian log-likelihood
logLik <- function(theta, Y, X){
  X           <- as.matrix(X) # convert data to matrix
  k           <- ncol(X) # get the number of columns (independent vars)
  beta        <- theta[1:k] # vector of weights intialized with starting values
  expected_y  <- X %*% beta  # X is dimension (n x k) and beta is dimension (k x 1)
  sigma2      <- theta[k+1] # should be pulled from the last of the starting values vector
  LL          <- sum(dnorm(Y, mean = expected_y, sd = sigma2, log = T)) # sum of the PDF over each observation
  return(-LL)
}

Answer 1

您的方法的基础是合理的，但有些细节是错误的。首先，根据高斯线性模型构造数据是有意义的;例如

set.seed(111)
X <- cbind(1, matrix(rnorm(100*3), 100, 3))
y <- X %*% rep(1, 4) + rnorm(100, 0, 2)

starting.values <- c(1, 1, 1, 1, 2) # actual parameters

# define gaussian log-likelihood
logLik <- function(theta, y, X){
  k           <- ncol(X) # get the number of columns (independent vars)
  beta        <- theta[1:k] # vector of weights intialized with starting values
  expected_y  <- X %*% beta  # X is dimension (n x k) and beta is dimension (k x 1)
  sigma      <- theta[k+1] # should be pulled from the last of the starting values vector
  LL          <- sum(dnorm(y, mean = expected_y, sd = sigma, log = TRUE)) # sum of the PDF over each observation
  return(-LL)
}

顺便说一下，*norm()函数是根据SD而不是方差进行参数化的。

然后

> optim(logLik, par=starting.values, y=y, X=X, method="BFGS")$par
[1] 1.0471420 1.1411523 0.8167656 0.9840397 1.8910201
Warning message:
In dnorm(y, mean = expected_y, sd = sigma, log = TRUE) : NaNs produced

> summary(lm(y ~ X - 1))

Call:
lm(formula = y ~ X - 1)

Residuals:
    Min      1Q  Median      3Q     Max 
-4.5062 -1.3293  0.1371  1.2057  5.8116 

Coefficients:
   Estimate Std. Error t value Pr(>|t|)    
X1   1.0471     0.1952   5.365 5.61e-07 ***
X2   1.1412     0.1818   6.275 1.00e-08 ***
X3   0.8168     0.1907   4.282 4.39e-05 ***
X4   0.9840     0.2122   4.638 1.11e-05 ***
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 1.93 on 96 degrees of freedom
Multiple R-squared:  0.5333,    Adjusted R-squared:  0.5138 
F-statistic: 27.42 on 4 and 96 DF,  p-value: 3.468e-15

请注意method="BFGS"发出警告但产生正确答案; method="Nelder-Mead"稍微不准确。另请注意，误差的SD的通常估计值与ML估计值不同。

我希望这会有所帮助

在R

1 个答案: