我有一个使用javascript setTimeout
从数据库获取数据的脚本,但我需要知道如何重新启动此setTimeot以再次检查数据库如何在不使用setInterval
的情况下执行此操作。
var update = 0;
var chatUpdate = setTimeout(function () {
$.ajax({
type: "GET",
url: "get_chat.php",
dataType: "html",
success: function (response) {
$(".msgView").html(response);
if (response !== lastResponse) {
var audio = new Audio('audio/solemn.mp3')
audio.play()
}
lastResponse = response
}
});
}, 2000);
感谢。
答案 0 :(得分:3)
您可以将函数设置为变量,然后再次调用setTimeout。
var update = 0;
var chatUpdate = function () {
$.ajax({
type: "GET",
url: "get_chat.php",
dataType: "html",
success: function (response) {
$(".msgView").html(response);
if (response !== lastResponse) {
var audio = new Audio('audio/solemn.mp3')
audio.play()
}
lastResponse = response
setTimeout(chatUpdate, 2000);
}
});
};
setTimeout(chatUpdate, 2000);
答案 1 :(得分:-1)
试试这个
var update = 0;
var chatUpdate = function () {
$.ajax({
type: "GET",
url: "get_chat.php",
dataType: "html",
success: function (response) {
$(".msgView").html(response);
if (response !== lastResponse) {
var audio = new Audio('audio/solemn.mp3');
audio.play();
}
lastResponse = response;
}
});
};
setTimeout(chatUpdate, 2000);