我有两张桌子加在一起:
SELECT
type,
name,
SUM(value) as total_value,
target,
target_month,
operator,
SUM(value_1) as total_value1,
AVG(average_of_total) as average
FROM
(SELECT
stats.`type`, stat_type.`target`, stat_type.`target_month`, stat_type.`operator`, stats.`monthly`, stats.`value`, stats.`value_1`, stats.`created_at`, `name`, stats.`average_of_total`
FROM
tefl_stats_customer as stats
JOIN
tefl_stats_customer_type as stat_type
ON
stats.`type` = stat_type.`id`) AS all_data
WHERE
created_at BETWEEN '20147-05-09 00:00:00' AND '2017-05-10 23:00:00' AND monthly = 0
GROUP BY `type`
目前正在回归:
| type | Name | total_value | target | target_month | operator | total_value1 | average |
| 12 | English | 3,378 | 400 | 8000 | <= | 0 | 0 |
| 9 | Chinese | 314 | 24 | 0 | = | 426 | 2.03698 |
| 1 | Japanese | 374 | 5 | 0 | < | 78 | 6.5 |
目前,正如您所看到的那样,&#39; 的 SUM()为 total_value 。
价值见表: tefl_stats_customer 。这个表有几千行。
如何获取上述查询中的最后一行并将其输出为 last_entry ?